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Answer:
I)E= 40.95 GPa
II)E=5.29 GPa
Explanation:
I)
Given that
E₁ = 2.41 GPa ,V₁=1-0.55 = 0.45
E₂ = 72.5 GPa ,V₂=0.55
Longitudinal moduli given as ;
E= E₁V₁+E₂V₂
E= 2.41 x 0.45 + 72.5 x 0.55 GPa
E= 40.95 GPa
II)
E₁ = 2.41 GPa ,V₁=1-0.55 = 0.45
E₂ =230 GPa ,V₂=0.55
Transverse moduli given as:
E=5.29 GPa
Answer:
35°c
Explanation:
Given data in question
heat = 35 kw
work = 35 kw
temperature = 35°c
To find out
temperature of the system after this process
Solution
we know that first law of thermodynamics is Law of Conservation of Energy
i.e energy can neither be created nor destroyed and it can be transferred from one form to another form
first law of thermodynamics is energy (∆E) is sum of heat (q) and work (w)
here we know
35 = 35 + m Cv ( T - t )
35-35 = m Cv ( T-t )
T = t
here T = final temperature
t = initial temperature
it show final temp is equal to initial temp
so we can say temp after process is 35°c
