Answer:
The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.
Explanation:
The Upper Surface Cp is given as
The Lower Surface Cp is given as
The difference of the Cp over the airfoil is given as
Now the Lift Coefficient is given as
Now the coefficient of moment about the leading edge is given as
So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.
Answer : The final velocity of the ball is, 12.03 m/s
Explanation :
By the 3rd equation of motion,
where,
s = distance covered by the object = 6.93 m
u = initial velocity = 2.99 m/s
v = final velocity = ?
a = acceleration =
Now put all the given values in the above equation, we get the final velocity of the ball.
Thus, the final velocity of the ball is, 12.03 m/s
Answer:
Explanation:
given data:
pressure 1 MPa
diameter of pipe = 30 cm
average velocity = 10 m/s
area of pipe
A = 0.070 m2
WE KNOW THAT mass flow rate is given as
for pressure 1 MPa, the density of steam is = 4.068 kg/m3
therefore we have
Answer: the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr
Explanation:
F, W and B are the fresh feed, brine and total water obtained
w = 2 x 10^4 L/h
we know that
F = W + B
we substitute
F = 2 x 10^4 + B
F = 20000 + B .................EQUA 1
solute
0.035F = 0.05B
B = 0.035F/0.05
B = 0.7F
now we substitute value of B in equation 1
F = 20000 + 0.7F
0.3F = 20000
F = 20000/0.3
F = 66666.67 kg/hr
B = 0.7F
B = 0.7 * F
B = 0.7 * 66666.67
B = 46,666.669 kg/hr
the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr