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dedylja [7]
3 years ago
13

Please help .. .... . ........​

Engineering
1 answer:
Helen [10]3 years ago
7 0

Answer:

how am i supposed to answer when there is no question?

Explanation:

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Tech A says that coolant circulates through some intake manifolds to help warm them up. Tech B says that some intake manifolds u
Nimfa-mama [501]

Answer:

Both Tech A and Tech B are correct.

Explanation:

In order to ensure that some intake manifolds have coolant running through them to assist them to warm up and to also ensure that an electric heater grid is used in some intake manifolds to warm up the intake air, a preheat grid is positioned between the intake manifold and throttle body.

This therefore implies that both Tech A and Tech B are correct. That is, it is true that coolant circulates through some intake manifolds to ensure that they warm up. And it is also true that some intake manifolds use an electric heater grid to warm up the intake air. This however occurs when a preheat grid is positioned between the intake manifold and throttle body.

8 0
3 years ago
What are four engineering degrees that can help lead you to becoming an aerospace engineer
mamaluj [8]

Answer:

Mechanical Engineering, Aerospace Engineering, Electrical Engineering, Aeronautical Engineering

Explanation:

I'm a Mechanical Engineer, and I considered Aerospace.

7 0
3 years ago
The volume of the pyramid is 36 cubic cm, find the volume of the prism.
ser-zykov [4K]

Answer:

Given :- the volume of the pyramid is 36 cubic cm , find the volume of the prism on same base and same height as pyramid .

Answer :-

we know that,

Volume of pyramid = (1/3) * Base area * height .

Volume of prism = Base area * height .

so,

→ Volume of pyramid = 36 cm³

→ (1/3) * Base area * height = 36

→ Base area * height = 36 * 3

→ Base area * height = 108 cm³.

then,

→ Volume of prism = Base area * height .

→ Volume of prism = 108 cm³ (Ans.)

Explanation:

5 0
3 years ago
What are the potential hazards relating to materials handling injuries?
Ann [662]

Answer:

it's says potential that something not moving.

incorrectly cutting ties or securing devices because

this is so dangerous thing I know because being electrocuted is here this for me.

8 0
3 years ago
the velocity of a particle is given by v=16t^2i+4t^3j+(5t+2k) m/s, where t is in seconds. if the particle is at the origin when
pshichka [43]

Answer:

80.16 m/s^2

at t=2 s

x=42.3 m

y=16 m

z=14 m

Explanation:

solution

The x,y,z components of the velocity are donated by the i,j,k vectors.

v_{x}=16t^{2}  \\v_{y}=4t^{3}\\v_{z}=5t+2

acceleration is a derivative of velocity with respect to time.

a_{x}=\frac{d}{dt} v_{x}=\frac{d}{dt}[16t^{2}]=32t\\a_{y}=\frac{d}{dt} v_{y}=\frac{d}{dt}[4t^{3}]=12t^{2} \\a_{z}=\frac{d}{dt} v_{z}=\frac{d}{dt}[5t+2]=5

evaluate acceleration at 2 seconds

a_{x} =32*2=64m/s^{2}\\ a_{y} =12*2^{2} =48m/s^{2}\\a_{z} =5m/s^{2}

the magnitude of the acceleration is the square root of the sum of the square of each component of the acceleration.

=\sqrt{a_{x}^2 +a_{y}^2+a_{z} ^2 } \\=\sqrt{64^2 +48^2+5 ^2 }\\=80.16m/s^2

position is the integral of velocity with respect to time position at a time can be found by taking by taking the definite intergral of each component.

x=\int\limits {v_{x} } \, dx=\int\limits^2_0 {{16t^2} \, dt=42.7m\\\\y=\int\limits {v_{y} } \, dx=\int\limits^2_0 {{4t^3} \, dt=16m\\\\\\\\\\z=\int\limits {v_{z} } \, dx=\int\limits^2_0 {{5t+2} \, dt=14m\\\\

3 0
3 years ago
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