Answer:
the question is incomplete, so I looked for a similar one:
<em>After the release of radioactive material into the atmosphere from a nuclear power plant, the hay was contaminated by iodine 131 ( half-life, 8 days). If it is all right to feed the hay to cows when 10% of the iodine 131 remains, how long did the farmers need to wait to use this hay? </em>
iodine's half life (we are given x, we need to find b):
0.5A₀ = A₀eᵇˣ
x = 8 days
we eliminate A₀ from both sides
0.5 = eᵇ⁸
ln 0.5 = ln eᵇ⁸
-0.69315 = b8
b = -0.69315 / 8 = -0.08664
since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):
0.1A₀ = A₀eᵇˣ
0.1 = eᵇˣ
ln 0.1 = bx
where b = -0.08664
x = ln 0.1 / -0.08664 = -2.302585 / -0.08664 = 26.58 days
X-int (-3,0)
Y-int (0,4/3)
Answer:
Length of rectangle = 10in.
Breadth " " =x
Perimeter= 2( l+b)=30in.
Perimeter=2(10+b)=30in.
=(10+b)=30/2=15
=b=15-10
Breadth=5in.
Answer:
D. (-1, 0) and (0, -6)
Step-by-step explanation:
The system of equations:
y = -6x - 6
y = x² - 5x - 6
We equate the two equations;
-6x - 6 = x² - 5x - 6
x² + x + 0 = 0
x² + x = 0
x(x + 1) = 0
So, x = 0 or -1
When x = 0,
Then y = -6(0) - 6 = -6
When x = -1,
Then y = -6(-1) - 6 = 6 - 6 = 0
So the answer is: (0, -6) and (-1, 0)
Answer:
-2
Step-by-step explanation:
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