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maw [93]
3 years ago
5

This unit focused, in part, on relationships in triangles. A triangle is the simplest type of

Mathematics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

triangles have a specific geometric shape.Because they have three sides, the pythagorean theorem for right angled triangle.

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4 people went to a restaurant. And the total bill for all of them is 106.9
olga_2 [115]

Answer:

26.725

Step-by-step explanation:

106.9/4

5 0
2 years ago
Read 2 more answers
HURRY HELP 18 POINTS
BlackZzzverrR [31]

Answer:

C. She did not follow order of operations.

Step-by-step explanation:

Order of operations says you always have to multiply before you add when solving an equation, unless there are parentheses. Meaning that she should have multiplied -9 and 2/5 first before adding -18, instead of adding -9 and -18 first.

7 0
3 years ago
Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper c
aalyn [17]

Answer:

a) This means that there is a 33% probability that one car chosen at random will have less than 49.5 tons of coal.

b) There is a 0.04% .probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The actual weights of coal loaded into each car are normally distributed, with mean = 50 tons and standard deviation = 0.9 ton. This means that \mu = 50, \sigma = 0.9

(a) What is the probability that one car chosen at random will have less than 49.5 tons of coal? (Round your answer to four decimal places.)

This is the pvalue of Z when X = 49.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{49.5 - 50}{0.9}

Z = -0.44

Z = -0.44 has a pvalue of 0.33.

This means that there is a 33% probability that one car chosen at random will have less than 49.5 tons of coal.

(b) What is the probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal? (Round your answer to four decimal places.)

Now we have to use the standard deviation of the sample, since we are working with the sample mean. That is

s = \frac{\sigma}{\sqrt{n}} = \frac{0.9}{\sqrt{35}} = 0.15

Now, we find pvalue of Z when X = 49.5

Z = \frac{X - \mu}{s}

Z = \frac{49.5 - 50}{0.15}

Z = -3.33

Z = -3.33 has a pvalue of 0.0004.

This means that there is a 0.04% .probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal

7 0
3 years ago
Vehicles leave an airport parking facility (arrive at parking fee collection booths) at a rate of 500 veh/h (the time between ar
Nutka1998 [239]

Answer:

At least 3 processing booths should be open.

Step-by-step explanation:

1 vehicle spends an average of 15 seconds in a booth

In N booths , there will be N/15 vehicles in 1 second

In 1 hr, there will be N/15 * 3600 vehicles

Therefore, there will be a total of 240N vehicles/hour

Actual arrival rate of vehicles at the airport is 500 veh/h

Probability of arrival, P = \frac{Number of possible outcomes}{Total outcomes}

P = 500/240N

P = 2.083/N

For the average time spends to be below 5 seconds

\frac{(\frac{P^{2} }{1-p} )}{500} = 5, since 500 is the average value.

\frac{P^{2} }{1-p} } = 2500\\P^{2} = 2500 (1-P)\\P^{2} = 2500 - 2500P\\(\frac{2.083}{N}) ^{2} = 2500 - 2500(\frac{2.083}{N})

2.083^{2} = 2500N^{2} - 5208N\\2500N^{2} - 5208N - 4.34 = 0

N^{2} -2.0832N - 0.0017 = 0

Solving for N using the quadratic formula with a = 1, b = -2.0832, c = -0.0017

N = \frac{-b \pm \sqrt{b^{2} -4ac} }{2a} \\N = \frac{2.0832 \pm \sqrt{(-2.0832)^{2} -4*1*(-0.0017)} }{2}

N = 1.0416 ± 1.0424

N = 2.084 or -0.0008

N = 2.084 is the only realistic value here

Therefore, the smallest number of processing booths that must be open should be 3

5 0
3 years ago
The sum of two integers is 17. Two times the greater is equal to 10 times one more than the lesser. Find the two numbers.
zysi [14]

Answer:

15 and 2

Step-by-step explanation:

15+2 is 17 and 15 multiplied by 2 is 30 and 2+1 is 3 and 3 x10 is 30. Ultimately, 30=30

6 0
3 years ago
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