Answer:-0.00714
Step-by-step explanation: STEP
1
:
1
Simplify —
5
Equation at the end of step
1
:
1
0 - — ÷ 7 ÷ 4
5
STEP
2
:
1
Divide — by 7
5
Equation at the end of step
2
:
1
0 - —— ÷ 4
35
STEP
3
:
1
Divide —— by 4
35
Equation at the end of step
3
:
1
0 - ———
140
STEP
4
:
Final result :
-1
——— = -0.00714
140
The correct answer would be that the statement is true. <span>The point-slope form of a line is y + y1 = m(x + x1), where m is the slope and (x1, y1) is a point on the line. This form of the equation of the line is helpful especially when you are asked to find the equation of the line given a point and the slope.</span>
Misleading may be present even t<span>hough all graphs may share the same data, and even the </span>slope<span> of the </span><span>data is the same. If the way the data is plotted is not correct, it can change the visual appearance of the angle made by the line on the graph. This is so because each plot has different scales on its vertical axis. As the scales are not correctly shown then there is where the misleading appears.</span>
Answer:
x ≈ -4.419
Step-by-step explanation:
Separate the constants from the exponentials and write the two exponentials as one. (This puts x in one place.) Then use logarithms.
0 = 2^(x-1) -3^(x+1)
3^(x+1) = 2^(x-1) . . . . . add 3^(x+1)
3×3^x = (1/2)2^x . . . . .factor out the constants
(3/2)^x = (1/2)/3 . . . . . divide by 3×2^x
Take the log:
x·log(3/2) = log(1/6)
x = log(1/6)/log(3/2) . . . . . divide by the coefficient of x
x ≈ -4.419
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A graphing calculator is another tool that can be used to solve this. I find it the quickest and easiest.
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<em>Comment on alternate solution</em>
Once you get the exponential terms on opposite sides of the equal sign, you can take logs at that point, if you like. Then solve the resulting linear equation for x.
(x+1)log(3) = (x-1)log(2)
x=(log(2)+log(3))/(log(2)-log(3))
Answer:
by alternating the density of the air and the vehical's speed.
Step-by-step explanation:
