Up to 12 people, p, can ride in the van.

you take a group of 20 people going to the movies. kids’ tickets cost $4 each, and adults tickets $6 each. your total cost is $9

brilliants [131]

The number of kids in your group is 12.

Step-by-step explanation:

Given,

Number of people = 20

Cost of each kid ticket = $4

Cost of each adult ticket = $6

Total spent = $96

Let,

x be the number of kids ticket

y be the number of adult ticket

According to given statement;

x+y=20 Eqn 1

4x+6y=96 Eqn 2

Multiplying Eqn 1 by 4

$4(x+y=20)\\4x+4y=80\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(4x+6y)-(4x+4y)=96-80\\4x+6y-4x-4y=16\\2y=16$

Dividing both sides by 2

$\frac{2y}{2}=\frac{16}{2}\\y=8$

Putting y=8 in Eqn 1

$x+8=20\\x=20-8\\x=12$

The number of kids in your group is 12.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

3 years ago

Due tonight Please help!!!!!

Harrizon [31]

angle BGC and angle BAD

7 0

3 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

3 years ago

If 3x - 2 = 13, what is the value of x? 0-5 • 5 0 -3.7 0 3.7

SIZIF [17.4K]

X=5 because you add 2 to both side and get 3x=15, and then you divide both sides by 3 to get x alone, and get 15/3 which equals 5

5 0

3 years ago

Read 2 more answers

Choose the fraction that has not been reduced to simplest form.

Gennadij [26K]

We are required to choose the fraction that has not been reduced to simplest form

The fraction that has not been reduced to simplest form is 19/38 and 10/18

1. 21 / 34 is in its simplest form

factors of 21 = 1, 7 and 21

factors of 34 = 1, 2, 17 and 34

No common factor of 21 and 34 except 1

2. 15/16

factors of 15 = 1, 3, 5, 15

Factors of 16 = 1, 2, 4, 8 and 16

No common factor of 15 and 16 except 1

3. 19/38

factors of 19 = 1, 19

factors of 38 = 1, 2, 19 and 38

divide both numerator and denominator by 19

So,

19 / 38 = 1/2

4. 10/18

factors of 10 = 1, 2, 5 and 10

factors of 18 = 1, 2, 3, 6, 9 and 18

So,

10/18

divide both numerator and denominator by 2

= 5/9