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cestrela7 [59]
3 years ago
5

A mass of 0.01 kg of steam at a quality of 0.9 is contained in the cylinder as shown in Figure 1 below. The spring just touches

the top of the piston. Heat is then added until the air expanded, and the spring is compressed by 15.7 cm. Calculate the final temperature of the steam in this cylinder. Sketch the process on a P-y and T-v diagrams with respect to saturation lines.​
Physics
1 answer:
malfutka [58]3 years ago
6 0
A mass of 0.01 kg of steam at a quality of 0.9 is contained in the cylinder as shown in Figure 1 below. The spring just touches the top of the piston. Heat is then added until the air expanded, and the spring is compressed by 15.7 cm. Calculate the final temperature of the steam in this cylinder. Sketch the process on a P-v and T-v diagrams with respect to saturation lines K = 50 kN/m 160 kg 20 cm Figure 1 Piston cylinder with spring
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A circuit connected to a battery of 1.9 voltage. has a current of 0.07 amps. What is the resistance
alexandr402 [8]

Answer:

27.14 ohms

Explanation:

V = IR

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The moon's illumination changes in a periodic way that can be modeled by a trigonometric function. On the night of a full moon,
kupik [55]

Answer:

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

Explanation:

The expression for the  trigonometric function is :

L(t) = A (cos (B(t - C)))+ D   ----- equation (1)

where ;

A = \frac{max-min}{2}

A = \frac{0.25-0}{2}

A = 0.125

D = \frac{0+.025}{2}

D = 0.125

Period of the lunar cycle = 29.53

Then;

\frac{2 \pi}{B}  = 29.53

29.53 \ \ B = 2 \pi

B = \frac{2 \pi}{29.53}

B = \frac{\pi}{29.53}

Also; we known that December 25 is 7 days before January 1.

Then L(-7) = 0.025

Plugging all the values into trigonometric function ; we have:

0.125 ( cos ( \frac{\pi}{14.765}((-7)-C)))+0.125 = 0.25 \\ \\ \\  ( cos ( \frac{\pi}{14.765}((-7)-C))) = \frac{0.25-0.125}{0.125}

( cos ( \frac{\pi}{14.765}((-7)-C))) = 1

( \frac{\pi}{14.765}((-7)-C))= cos^{-1} (1)

}((-7)-C))=0

C= -7

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t-(-7))) + 0.125

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

7 0
3 years ago
The electron dot diagram shows the arrangement of dots without identifying the element.
olasank [31]

<em>Answer: </em>tellurium (Te)

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<em>Number of energy levels = 5;</em>

              First energy level = 2

         Second energy level = 8

             Third energy level = 18

           Fourth energy level = 18

               Fifth energy level = 6

<em>In this electron configuration, 0uter most electrons are 6.</em>


5 0
3 years ago
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Weathering and rock slides
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A ladder 7.60 m long leans against an exterior wall. If the ladder is inclined at an angle of 68.0° to the horizontal, what is t
nata0808 [166]

Answer:

2.85 m

Explanation:

From trigonometry,

Cosine = Adjacent/Hypotenuse

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cos∅ = a/H....................... Equation 1

Where ∅ = Angle the ladder makes with the horizontal, a = The horizontal distance from the bottom of the ladder to the wall, H = The length of the ladder.

make a the subject of the equation

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Given: ∅ = 68 °, H = 7.6 m.

Substitute into equation 2

a = cos(68)×7.6

a = 0.375×7.6

a = 2.85 m.

Hence the horizontal distance from the bottom of the ladder to the wall = 2.85 m

8 0
3 years ago
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