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2 years ago

Which of the following circuits will stop producing light if one bulb burns out? *

Physics

1 answer:

gulaghasi [49]2 years ago

6 0

Answer:

Circuit 1 and Circuit 3

Explanation:

If there is 1 Circuit and it runs out of energy, there's another one to produce the power.

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A unit mass of an ideal gas at temperature T undergoes a reversible isothermal process from pressure P1 to pressure P2 while los

mafiozo [28]

Answer:

Option B

Change in entropy of the process is $\Delta S= Rln(\frac{P_{1}}{P_{2}})$

Explanation:

The entropy of a system is a measure of the degree of disorderliness of the system.

The entropy of a system moving from process 1 to 2 is given as

$\Delta S = \int\limits^2_1 {\frac{\delta q}{T}}$

recall from first law, $\delta q =du +Pdv$

hence we have, $\Delta S = \int\limits^2_1 {\frac{du +Pdv}{T}}$

since the process is isothermal, $du= 0$

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integrating within the limits of 1 and 2, will give us

$\Delta S = R ln (\frac{V_{2}}{V_{1}})$

also from ideal gas laws,

$\frac{V_{2}}{V_{1}}=\frac{P_{1}}{P_{2}}$

hence we have $\Delta S = R ln (\frac{P_{1}}{P_{2}})$

This makes the correct option B

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An atom of gadolinium has an atomic number of 64 and a mass number of 154. how many electrons, protons, and neutrons does it con

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3 years ago

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