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olchik [2.2K]
2 years ago
7

Which of the following circuits will stop producing light if one bulb burns out? *

Physics
1 answer:
gulaghasi [49]2 years ago
6 0

Answer:

Circuit 1 and Circuit 3

Explanation:

If there is 1 Circuit and it runs out of energy, there's another one to produce the power.

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What is the next step if the data from an investigation do not support the original hypothesis? A. The data are revised to suppo
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When you enter a toll road, your ticket is stamped 1:00 p.m. When you leave, after traveling 55 miles, your ticket is stamped 2:
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Differences between weightlessness in space and weightlessness in earth​
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"In a pure substance all the particles must be identical; therefore pure substances are composed only of elements." Do you agree
kenny6666 [7]

I do not agree with the statement.
The "substance" can be a compound.  It's "pure"
as long as there's nothing else in it but its name.

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6 0
3 years ago
At 1 atm pressure, the heat of sublimation of gallium is 277 kj/mol and the heat of vaporization is 271 kj/mol. to the correct n
Andreyy89
Below are the choices that can be found elsewhere:

 a. 268 kJ 
<span>b. 271 kJ </span>
<span>c. 9 kJ </span>
<span>d. 6 kJ
</span>
So the key thing to realize here is what the information given to you actually means. Sublimation is going from a sold to a gas. Vaporization is going from a liquid to a gas. Hence you can create two equations from the information that you have: 

<span>Ga (s) --> Ga (g) delta H = 277 kJ/mol </span>

<span>Ga (l) --> Ga (g) delta H = 271 kJ/mol </span>

<span>From these two equations, you can then infer how to get the melting equation be simply finding the difference between the sublimation (two steps) and vaporization (one step). </span>

<span>Ga (s) --> Ga (l) delta H = 6 kJ/mol </span>

<span>At this point, all you need to do is a bit of stoichiometry. You start with 1.50 mol and multiply by the amount of energy per mole (6 kJ/mol). </span>

<span>*ANSWER* </span>
<span>9 kJ/mol (C)</span>
7 0
3 years ago
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