That will depend, you have to ask yourself first how many kilobytes one picture is. Let's just say that the size of one picture is 100 kb (which is the average size of a picture) Then first you multiply 100 kb with the number of pictures which is 43. Now you have a total used up memory of 4300 kb. After that, you minus the used up memory which is 4300 kb, to the total available space which is 32,834.5 and you will get an available space of 28534.5 kb. After that, you divide the remaining available space with the size of each picture. So this will be 28534.5 divided by 100. You will get 285. You can still take 285 pictures.
Answer:
1: 216 selections
2: 120 selections
Step-by-step explanation:
1:
we have 6 different colors and we can choose the same color repeatedly, so for each of the 3 dogs, we have 6 possibilities, so the number of combinations is 6*6*6 = 216 selections.
2:
we have 6 different colors and we can't repeat a color, so the first collar has 6 possibilities, the second has 5 possibilities (one color was already chosen), and the third collar has 4 possibilities (two already chosen), so the number of selections is 6*5*4 = 120.
Answer:
Solving 14t-3t we get 22 and 3t-14t we get -22
So, 14t-3t is not equivalent to 3t-14t.
Step-by-step explanation:
We need to explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.
<em>Equivalent expressions are those that have same values for any value of variable substituted.</em>
Now, We check if our expressions are equivalent, by evaluating the expression for t=2.
If they are equivalent, they would have same result after evaluation.
First, put t=2 into 14t-3t
Now put t=2, into 3t-14t
For solving 14t-3t we get 22 and 3t-14t we get -22
So, 14t-3t is not equivalent to 3t-14t.
There would be 2 doves and 4 parrots.
2 + 4 = the 6 in total, and the ratio between doves (2) and parrots (4) is 1 to 2 because the ratio of 2 to 4 is equal to 1 to 2.
