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2 years ago

Will mark brainliest please help

Mathematics

2 answers:

Kruka [31]2 years ago

3 0

Option A

Opposite angles in a cyclic quadrilateral add up to 180°

her

x and 133 are opposite angles

x+133=180
x=180-133
x=47°

Part A is done after part B

Juliette [100K]2 years ago

3 0

Answer:

Quadrilateral: A two-dimensional shape with 4 straight sides and 4 interior angles.

Cyclic Quadrilateral: A quadrilateral drawn inside a circle where every vertex of the quadrilateral touches the circumference of the circle.

We know that opposite angles in a cyclic quadrilateral are supplementary, which means their sum is 180°

Therefore:

⇒ x + 133° = 180°

⇒ x = 180° - 133°

⇒ x = 47°

Opposite angles in a cyclic quadrilateral add up to 180°

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3 years ago

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Consider the following equations and name the property of equality used to solve for the variable.

Viktor [21]

9514 1404 393

Answer:

A. subtraction

B. division

C. multiplication

D. addition

Step-by-step explanation:

Observe what is done to the variable. Choose the operation that turns the unwanted value into the appropriate identity element.

A. 3.75 is added. To make that value be 0, we subtract 3.75.

B. -3 is multiplied. To make that value be 1, we divide by -3.

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5 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

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3 years ago

Use Synthetic substitution to find f(3) and f(-4) for f(x)=x^4-8x-11

brilliants [131]

Answer:

46 and 277

Step-by-step explanation:

Given

f(x) = $x^{4}$ - 8x - 11 ← substitute x = 3, x = - 4 into f(x)

f(3) = $3^{4}$ - 8(3) - 11 = 81 - 24 - 11 = 81 - 35 = 46

f(- 4) = $(-4)^{4}$ - 8(- 4) - 11 = 256 + 32 - 11 = 288 - 11 = 277

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2 years ago

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sergiy2304 [10]

Answer:

x = 1&16

Step-by-step explanation:

f(x) = 0 then

0 =x^2 - 17x + 16

(x-1)(x-16) =0

x -1 =0 or x-16=0

x =1 & x = 16

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3 years ago

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