Answer:
O.186 or 18.6%
Step-by-step explanation:
Let s = event of schizophrenia
B = brain atrophy
From our question we have:
P(s) = probability of those suffering from schizophrenia = 1.5% = 0.015
P(B|S) = probability of brain atrophy = 30% = 0.30
P(S') = 1 - 0.015 = 0.985
P(B|S') = 2% = 0.02
Probability Hinckley suffered from schizophrenia
= P(S|B) = P(B|S)P(S)/P(B|S)P(S)+P(B|S')P(S')
= (0.30x0.015)/(0.30)*(0.015)+(0.02)(0.985)
= 0.0045/0.0045+0.0197
= 0.0045/0.0242
= 0.185950
This is approximately 0.186 or 18.6%
F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21
The solution is -0.609611 and -1.64, I do not think you can simply find this by factoring but the only way is graphing it
