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balu736 [363]
3 years ago
5

A line intersects the points

Mathematics
1 answer:
monitta3 years ago
3 0

The slope of this line in  its simplest form is -3.

<u>Given the following points:</u>

  • Points on the x-axis = (7, 11)
  • Points on the y-axis = (6, -6)

To determine the slope of this line in  its simplest form:

The slope of a line refers to the gradient of a line and it describes both the direction and steepness of an equation of a straight line.

Mathematically, the slope of a line is calculated by using this formula;

Slope. \;m = \frac{Change \; in \; y \;axis}{Change \; in \; x \;axis} \\\\Slope. \;m = \frac{y_2 - y_1}{x_2 - x_1}

Substituting the given parameters into the formula, we have;

Slope, \;m  = \frac{-6 - 6}{11 - 7}\\\\Slope, \;m  = \frac{-12}{4}\\

Slope, m = -3.

Read more on slope here: brainly.com/question/3493733

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Answer:

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4 years ago
On square PQRS below, if Q is located at (7,0) and R is located at (5,-8) what is the length of SR
jenyasd209 [6]

the length of SR is 2\sqrt{17} .

<u>Step-by-step explanation:</u>

Here we have , On square PQRS below, if Q is located at (7,0) and R is located at (5,-8) . We need to find Length of side SR . Let's find out:

We know  that  , In a square there are  4 sides , and length of every side is same . So side length of SR = side length of QR . Now , Let's find side length of QR .

We know that distance between two points Q(x_1,y_1),R(x_2,y_2) given by :

⇒ QR = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Two points given are Q(7,0), R(5,-8) :

⇒ QR = \sqrt{5-7)^2+(-8-0)^2}

⇒ QR = \sqrt{(2)^2+(-8)^2}

⇒ QR = \sqrt{4+64}

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Answer:

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