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Verizon [17]
3 years ago
7

a photo masured 15cm by 10cm andbis put in a frame that measures 25cm by 20cm calculate the are of the space between the photogr

aph and the frame
Mathematics
1 answer:
Oliga [24]3 years ago
5 0
The frame is 25x20cm, meaning hat it has an area of 500. The photo is 15x10, meaning it has an area of 150. Therefore, if you subtract the areas (500-150) you get an area between the photograph of 350 cm squared.
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What is the slope and y-intercept of y=4x+2
kaheart [24]

Answer:

slope: 4

y-intercept: 2

Step-by-step explanation:

We are given an equation, y = 4x + 2, and we are asked to find the slope and y-intercept of the line. Looking carefully, we can see that the equation is given to us in slope-intercept form.

Slope-intercept form is:

y = mx + b

where m is the slope and b is the by-intercept.

Knowing this, we can find that 4 is the slope of the line and 2 is the y-intercept.

I hope you find my answer and explanation to be helpful. Happy studying.

4 0
3 years ago
How do you make x+2y=6 a linear equation
madreJ [45]
Subtract X
2y=-x+6
Then divide by 2
Y=-1/2x+3
5 0
3 years ago
Read 2 more answers
I don't know to find the answer to 8. Can someone explain to me?
lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
7 0
2 years ago
find an expression for the area of a rectangle of sides 2x+3 and x-1 given that the perimeter is 28cm what is the value of x
Ierofanga [76]

Answer:

4cm

Step-by-step explanation:

Given data

L=(2x+3)

W=(x-1)

P=28cm

A= L*W

A= (2x+3)*(x-1)

open bracket

A= 2x^2-2x+3x-3

collect like terms

A= 2x^2+x-3

P= 2L+2W

P= 2*(2x+3)+2(x-1)

P= 4x+6+2x-2

collect like terms

P= 6x-4

but p= 28

28= 6x-4

28-4= 6x

24= 6x

x= 24/6

x= 4cm

Hence x= 4cm

4 0
2 years ago
HCF of 405 and 1605 answer it fast
Rashid [163]

Answer:

hcf=(1,605; 600) = 3 × 5

Step-by-step explanation:

Prime Factorization of a number: finding the prime numbers that multiply together to make that number.

1,605 = 3 × 5 × 107;

1,605 is not a prime, is a composite number;

600 = 23 × 3 × 52;

600 is not a prime, is a composite number;

* Positive integers that are only dividing by themselves and 1 are called prime numbers. A prime number has only two factors: 1 and itself.

* A composite number is a positive integer that has at least one factor (divisor) other than 1 and itself.

Multiply all the common prime factors, by the lowest exponents (if any).

gcf, hcf, gcd (1,605; 600) = 3 × 5

gcf, hcf, gcd (1,605; 600) = 3 × 5 = 15;

The numbers have common prime factors.

Must mark brainliest for more answers.

And you should friend me.

7 0
2 years ago
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