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2 years ago

10

A sign along the highway says 6% grade for the next 7 mi. How many feet of vertical change there are along those 7 miles. (5280

feet

1 answer:

Tasya [4]2 years ago

6 0

Answer:

Step-by-step explanation:

The length of the road is 7 * 5280 = 36960 feet

The grade is 6% which means that for every 100 feet horizontally, the road rises 6 feet.

6/100 * 36960 = 221760/100 = 2217.6 is the rise.

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the table tells us that 4 students had no siblings 5 students had one sibling, 14 students had two siblings and so on

Hatshy [7]

The answer is 8000383890

7 0

3 years ago

3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)

sveta [45]

Answer:

For the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

Step-by-step explanation:

Here, the given function are:

$f(x) = 3x^{2} - 2x+ 4\\g(x) = 5x^{2} + 6x -8$

Now, simplifying for (f-g)(x) = f(x) - g(x):

$f(x) - g(x) = (3x^{2} - 2x+ 4) - (5x^{2} + 6x -8)$

$= 3x^{2} - 2x+ 4- 5x^{2} - 6x +8$

Doing operation on LIKE TERMS, we get

f(x) - g(x) = $( 3x^{2}- 5x^{2}) + (-2x - 6x) +( 4 +8) = -2x^{2} - 8x + 12$

Hence, for the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

4 0

3 years ago

34.98+12.24=?<br>answers please

Ksivusya [100]

Answer:

Hello!

After reading your question I have calculated the correct answer to be:

47.22

Step-by-step explanation:

The way I solved this equation was I first split the equation into two parts.

I took the two whole numbers, being "34" and "12", and made their own equation:

"34+12=?"

And then I took the two partial numbers "0.98" and "0.24" and made their own equation:

"0.98+0.24=?"

I then solved both equations:

"34+12= 46"

"0.98+0.24= 1.22"

And added those two solutions together to come up with the final solution:

"46+1.22= 47.22"

Hope this helped!

6 0

2 years ago

Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited thre

Lera25 [3.4K]

Answer:

$36 400

Step-by-step explanation:

Step 1

The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.

The amount deposited in January is $\$100.$

The amount deposited in February is $1\$00\times 3= \$300.$

The amount deposited in March is $\$300\times 3= \$900.$

The amount deposited in April is $\$900\times 3= \$2\700.$

The amount deposited in May is $\$2\,700\times 3= \$8\,100.$

The amount deposited in June is $\$8\,100\times 3= \$24\,300.$

Step 2

The next step is to add up all the money that was deposited into the account. This calculation is shown below,

$\$100+\$300+900+\$\$2\,700+\$8\,100+\$24\,000=\$36\,400$

5 0

3 years ago

Read 2 more answers

SOMEONE PLZ HELP ME!!!! I WILL GIVE BRAINLIEST!!!

MAXImum [283]

Answer:

Step-by-step explanation:

Let the quadratic equation of the function by the points in the given equation is,

f(x) = ax² + bx + c

If the points lying on the graph are (-3, -10), (-4, -8) and (0, 8),

For (0, 8),

f(0) = a(0)² + b(0) + c

8 = c

For a point (-3, -10),

f(-3) = a(-3)² + b(-3) + 8

-10 = 9a - 3b + 8

9a - 3b = -18

3a - b = -6 --------(1)

For (-4, -8),

f(-4) = a(-4)² + b(-4) + 8

-8 = 16a - 4b + 8

-16 = 16a - 4b

4a - b = -4 ------(2)

Subtract equation (1) from equation (2)

(4a - b) - (3a - b) = -4 + 6

a = 2

From equation (1),

6 - b = -6

b = 12

Function will be,

f(x) = 2x² + 12x + 8

= 2(x² + 6x) + 8

= 2(x² + 6x + 9 - 9) + 8

= 2(x² + 6x + 9) - 18 + 8

= 2(x + 3)² - 10

By comparing this function with the vertex form of the function,

y = a(x - h)² + k

where (h, k) is the vertex.

Vertex of the function 'f' will be (-3, -10)

And axis of symmetry will be,

x = -3

From the given graph, axis of the symmetry of the function 'g' is; x = -3

Therefore, both the functions will have the same axis of symmetry.

y-intercept of the function 'f' → y = 8 Or (0, 8)

y-intercept of the function 'g' → y = -2 Or (0, -2)

Therefore, y-intercept of 'f' is greater than 'g'

Average rate of change of function 'f' = $\frac{f(b)-f(a)}{b-a}$ in the interval [a, b]

= $\frac{f(-3)-f(-6)}{-3+6}$

= $\frac{-10-8}{3}$

= -6

Average rate of change of function 'g' = $\frac{g(b)-g(a)}{b-a}$

= $\frac{g(-3)-g(-6)}{-3+6}$

= $\frac{7+2}{-3+6}$

= 3

Therefore, Average rate of change of function 'f' is less than 'g'.

6 0

3 years ago