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elena-s [515]
2 years ago
7

What is the domain of the function

Mathematics
1 answer:
mixas84 [53]2 years ago
3 0

Answer:

  (a)  -∞ < x < ∞

Step-by-step explanation:

Unlike the square root function, the cube root function is defined for all values of its argument. Here, x can take on any value and the function will be defined for that value.

  -∞ < x < ∞

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5 0
2 years ago
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Is 0.48 greater than 11/25
Zina [86]
0.48=48/100=12/25~~~12/25>11/25 True✔ ~~~~Have a nice day!!! ★★
8 0
3 years ago
Pls answer this i need help
Vitek1552 [10]

Step-by-step explanation:

your don't see what went wrong ?

Tyrell worked on

16 - 2(4 + 3x)

what do brackets mean ? they mean that this operation has to be done before everything else in the expression.

as this contains a variable, we cannot fully calculate it, true, but we need to keep this in mind and always treat the content of the brackets as one package.

so, whatever I do from the outside with one part of that package, I have to do also with all the other parts of that package.

so, the multiplication with -2 has to happen with both : 4 and 3x. not just with 4.

therefore, the correct simplification looks like

16 - 8 - 6x

8 - 6x or -6x + 8

Amelia multiplied correctly, but then made a mistake summing things up

10x - 3(4x + 1)

10x - 12x - 3

10x - 12x = -2x

I can't mix the pure constant -3 into the factors of x. that would be like the famous mixing of apples and oranges.

so, the result is

-2x - 3

6 0
3 years ago
5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.​
lesya692 [45]

9514 1404 393

Answer:

  ±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

  |x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

  sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

  A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

  A·cos(c) = 3   and   A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

  (A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

  x = A·sin(θ +c) . . . . for some angle c

  x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0
3 years ago
Draw a diagram using positive an negative tiles for this equation:<br> -5-(-7)=2
Wewaii [24]
Sadly there is no way to graph properly on this website.
5 0
2 years ago
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