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2 years ago

Help.................................................

Mathematics

1 answer:

velikii [3]2 years ago

6 0

Answer:

3 newtons to the left

Step-by-step explanation

since the arrows are pointing towards each other you have to subtract

5-2=3

Since five is the greatest number it will be pushing to the left

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Can anyone help me find the value pls?

Flauer [41]

The inside angle for B, which is labeled x is the same as the outside angle of D which is labeled as 72, so we know x = 72.

In a parallelogram two angles next to each other equal 180, so angle A and angle B equal 180.

We know B = 72, so A = 180-72 = 108

Angle A is divided in 2 by angle y, so y = 108/2 = 54

Answers: x = 72

Y = 54

4 0

2 years ago

A star in the sky appears to move by 12 arcseconds over the course of 6 months. Convert this number into first areminutes then d

Bumek [7]

Answer:

Given :A star in the sky appears to move by 12 arc seconds over the course of 6 months.

To Find :Convert this number into first arc minutes then degrees.

Solution:

60 arc seconds = 1 arc minute

1 arc seconds = $\frac{1}{60}$ arc minute

12 arc seconds = $\frac{1}{60} \times 12$ arc minute

12 arc seconds = $\frac{1}{5}$ arc minute

So, 12 arc seconds = $\frac{1}{5}$ arc minute

Now convert it into degrees

60 arc minute = 1 degree

1 arc minute = $\frac{1}{60}$ degree

$\frac{1}{5}$ arc minute = $\frac{1}{60} \times \frac{1}{5}$ degree

$\frac{1}{5}$ arc minute = $\frac{1}{300}$ degrees

12 arc seconds = $\frac{1}{300}$ degrees

8 0

3 years ago

What number represents the same amount as 2 hundreds ++plus 14 tens ++plus 3 ones?

Dennis_Churaev [7]

343 is the answer because 14 tens is 1 hundred and 4 tens

4 0

3 years ago

Find the reference angle for a rotation of 320°.

Fiesta28 [93]

Answer:

<u>40°</u>

Step-by-step explanation:

8 0

2 years ago

An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0

2 years ago