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3 years ago

A quadrilateral has two angles that measure 200 and 30°. The other two angles are in a

Mathematics

1 answer:

Ad libitum [116K]3 years ago

8 0

Answer:

60 and 70°

Step-by-step explanation:

the angle sum of a quadrilateral is 360

200°+30°+6x+7x=360°

13x=130°

x=10°

1st angle: 10°×6=60°

2nd angle: 10°×7=70°

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Four times a number plus six times a number is equal to 8 times a number plus thirty four

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Find the axis of symmetry and the vertex of the graph of f(x)=−6x2+24x−20

asambeis [7]

The vertex will be when the velocity is equal to zero:

df/dx=-12x+24 (using the power rule for differentiation)

df/dx=0 only when:

-12x+24=0 add 12x to both sides

12x=24 divide both sides by 12

x=2, we find the y value to be:

y(2)=-6(2^2)+24*2-20

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So the vertex is the point (2,4)

And the axis of symmetry is the line x=2

Now if you do not yet do calculus...

The vertex will occur midway between the two zeros.

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x≈(1.1835, 2.8165)

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3 years ago

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Help meh wit this bruh‍♂️

Leno4ka [110]

Answer:

a) m∠BPD = 120°

b) m∠BC + m∠AD = 120°

Step-by-step explanation:

a) To solve for question a, we make use of a theorem called the intersecting chord theorem. This states that:

The measure of the angle formed by two chords that intersect inside a circle is the average of the measures of the intercepted arcs.

The Interior angle =( The larger exterior arc + The smaller exterior arcs) ÷ 2

The larger exterior arc (m∠BD) = 170°

The small exterior arc (m∠CA) = 70°

m∠BPD = m∠BD + m∠CA/2

m∠BPD = 170° + 70°/2

= 240°/2

= 120°

b) We are to find m∠BC + m∠AD

The sum of exterior angles in a circle = 360°

360° = m∠BD + m∠CA + m∠BC + m∠AD

360° = 170° + 70° + m∠BC + m∠AD

360° = 240 + m∠BC + m∠AD

360 - 240° = m∠BC + m∠AD

Thererefore,

m∠BC + m∠AD = 120°

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Help asap show work i will make u brainlest.

Mariulka [41]

Answer: (10) C (11) D (12) B (13) D (14) C (15) A

Step-by-step explanation:

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-3 -3

- 7 | -1 + 2x| = -119

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-1 + 2x = 17 or -1 + 2x = -17

+1 +1 +1 +1

2x = 18 2x = -16

÷2 ÷2 ÷2 ÷2

x = 9 or x = -8

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