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2 years ago

Why do you think industrial leaders are reluctant to hire new graduates?

Advanced Placement (AP)

1 answer:

Temka [501]2 years ago

5 0

Answer:

Employers don't want to train their employees because they fear they'll leave the company — which employees are actually doing more and more frequently these days — which means all the effort and expense of the training process will be wasted.

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7. If Kaci finds $1,000 under her bed and deposits in a bank, what is the total

dexar [7]

The change is 0!!!!!!!!

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2 years ago

I want there to be an answer here AT THE EXACT time of 5 MINUTES no short no late

inessss [21]

I mean put in the work to get your questions answered fast

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3 years ago

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1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a NET DECREASE of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.

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2 years ago

Which stage of mitosis is known as the “preparing to divide” stage?

cestrela7 [59]

The phase in meiosis that is termed this would be telophase, as it is during this phase, the opposite operations as what happened in the prophase is happening here.

The only other part is for the cytoplasm to be cleaved off through different mechanisms.

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3 years ago

When securing the vehicle, what should be the first task

frosja888 [35]

The first task should be done while securing the vehicle is stopping in a legal, secure, parking space.So that we can avoid conflicts in parking the vehicles.Parking in a legal space will be the extra security for our vehicle.There is no any traffic collisions while taking or parking the car.Then police won't charge any fine for our vehicle if we park in legal space.

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3 years ago

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