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2 years ago

1/15 plus 1/5 plus 1/3 is equals to?

Mathematics

2 answers:

nydimaria [60]2 years ago

6 0

Answer:

⅗

... ... ... ...

NeX [460]2 years ago

3 0

The answer is 9/15 but when you simplify it it turns to 3/5

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martina and charlotte are sharing a pizza. Th e pizza is cut into eight pieces. Martina ate a quarter of the pizza. Charlotte at

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3 slices are left because a quarter of the 8 is 2 so there is 6 left than 6-3=3 so 3 slices are left

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3 years ago

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Which statement is sometimes, but not always, true?

lidiya [134]

The statement that is sometimes, but not always true is:
B ) A parallelogram is a rectangle.
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4 years ago

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In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

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3 years ago

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Answer:

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3 years ago