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Orlov [11]
3 years ago
13

Square root -80 by using imaginary unit I

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0
You already got the answer but if you ever need the answer instantly for any math question use mathaway its a really good app and will gove you the answer and step by step explanation
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What is the approximate volume of the sphere​
NISA [10]

Answer:

523.33 mm³

Step-by-step explanation:

The general formula for the volume of a sphere is:

V = \frac{4}{3}\pi r^{3}

The radius for the given sphere is 5mm, so plugging that value into the equation and using 3.14 for π:

V = \frac{4}{3}(3.14)(5^{3})

V ≈ 523.33 mm³

8 0
3 years ago
HELP FAST PLS I’ll mark u brainliest
Vesnalui [34]

Answer:

about 20 cents

Step-by-step explanation:

4 0
2 years ago
Two neighbors, wilma and betty, each have a swimming pool. both wilma's and betty's pools hold 9900 gallons of water. if wilma's
s2008m [1.1K]
To solve this problem we will start by calculating time needed for each of them to fill the pool.

We have formula:
Volume = rate * time
Or
time = volume / rate

Wilma:
time = 9900 / 900
time = 11h

Betty:
time = 9900 / 500
time = 19.8h

Now we substract these two numbers:
time_difference = 19.8 - 11 = 8.8h

Betty needs 8.8 hours more than Wilma to fill the pool.
3 0
3 years ago
A taxi driver charges a flat rate of $3.50 plus an additional $1.65 per mile. If Mohammad wants to spend, at most, $60, how far
Elena-2011 [213]

Answer:

11.6 should be your answer!

Step-by-step explanation:

Im so sorry if its wrong!

Hope this helps!!

( > .< )

6 0
3 years ago
A quality control inspector has drawn a sample of 19 light bulbs from a recent production lot. If the number of defective bulbs
Inessa05 [86]

Answer:

0.0016283

Step-by-step explanation:

Given that:

Proportion of defective bulbs, p = 30% = 0.3

Sample size, n = 19 bulbs

Probability that the lot will pass inspection :

P(none of the 19 is defective) Or P(only one of the 19 is defective)

P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19

0.7^19 = 0.0011398

P(only one of the 19 is defective) :

P(1 defective) * P(18 not defective )

(0.3) * (1 - 0.3)^18

0.3 * 0.7^18

0.3 * 0.001628413597910449 = 0.0004885

Hence,

P(none of the 19 is defective) + P(only one of the 19 is defective)

0.0011398 + 0.0004885) = 0.0016283

8 0
3 years ago
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