Hey There!
<h2><u>Question:-</u></h2>

<em>This is a algebraic expression. The values of a and b are given. The values are as follows :-</em>
a = -1
And,
b = +5 .
<h2><u>Solution</u><u>:</u><u>-</u></h2>

<em>Note that </em><u>a </u><em>is multiplied with 2 that is :-</em>

<u>Now, Insert the values that is a = -1 and b = 5 :-</u>

Here,we need to follow BODMAS Rule.
B = Brackets
O = Orders
D = Division
M = Multiplication
A = Addition
S = Subtraction
<em>We need to solve the bracket's </em><em>calculations</em><em> </em><em>first</em><em> </em><em>as </em><em>it </em><em>is </em><em>the</em><em> </em><em>rule.</em>
<u>So, Firstly Multiply (2 × -1)</u><u> </u><u>:</u><u>-</u>

Note that, (-) × (-) equals to (+).
So, it will be 5+2,But as 5 is bigger number than 2, 5 contains a minus sign.So the result will be -7.

<em>On Simplification:-</em>



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<em>Henceforth the solution of the algebraic expression is :-</em>

Option B is correct!
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I hope this helps!
Please let me know if you have any questions.
~MisterBrian