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uysha [10]
2 years ago
6

The square root of the sum of two consecutive odd integers is equal to 6. Find the larger integer.

Mathematics
1 answer:
o-na [289]2 years ago
3 0
67 is the larger one because that is the right answer or it could be 6
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2 years ago
WILL AWARD BRAINLIEST ANSWER
Tpy6a [65]

Answer:

(x - 5)^2 + (y - 7)^2 = 13^2

or

(x - 5)^2 + (y - 7)^2 = 169

Step-by-step explanation:

Well, the center origin of the circle is given (h,k) =  (5,7).

We have to find our radius as they gave us a point. from origin to the edge of the circle.

Using the formula: (x - h)^2 + (y - k)^2 = r^2

Plug in our (h,k) = (5,7) and (x,y) =  (10,19) to solve for radius.

(x - h)^2 + (y - k)^2 = r^2

(10 - (5))^2 + (19 - (7)^2 = r^2

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KatRina [158]

Answer:

(7a^2 + 8b^2 + 5ab) (7a^2 + 8b^2 - 5ab)

Step-by-step explanation:

Dado que ambos términos son cuadrados perfectos, puede factorizar utilizando la fórmula de la diferencia de cuadrados, a^2 - b^ 2 = (a + b) (a - b), donde a = 7a^2 + 8b^2 y b = 5ab.

English: Since both terms are perfect squares you can factor using the difference of squares formula, a^2 - b^2 = (a + b)(a - b), where a = 7a^2 + 8b^2 and b = 5ab.

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Step-by-step explanation:

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Step-by-step explanation:

(-1 , 6)  ; (-1 , -5)

There is no change in x-coordinate values.

So, the is parallel to y-axis

x = -1

         

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2 years ago
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