3 years ago

The square root of the sum of two consecutive odd integers is equal to 6. Find the larger integer.

1 answer:

o-na [289]3 years ago

3 0

67 is the larger one because that is the right answer or it could be 6

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DerKrebs [107]

2876 Rounds To 3000
513 Rounds To 500
18 Rounds To 20
Then multiply:
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3 years ago

KatRina [158]

The answer is B so if you need help call me and i will help you are welcomed

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3 years ago

stepan [7]

Answer:

x=165

Step-by-step explanation:

Multiply both sides by 15

15(x/15)=11*15

x=165

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4 years ago

Alex787 [66]

4x-3y =36

Move the constant to the left by adding its opposite to both sides

4x-3y-36=36-36

The sum of two opposites equals 0

Answer: 4x-3y-36=0

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3 years ago

Diano4ka-milaya [45]

Simplify the expression

$(5*10^5)^-2$

It can be simplified as below:

$(5*10^5)^{-2}=\frac{1}{(5*10^5)^2} \\\\(5*10^5)^{-2}=\frac{1}{25*10^{10}} \\\\(5*10^5)^{-2}=\frac{1}{25}*10^{-10}\\\\ (5*10^5)^{-2}=0.04*10^{-10}\\$

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3 years ago