Answer:
Given:
Radius of large sphere: R1
Volume of sphere: V1
Radius of small sphere: R2
Volume of sphere: V2
R1=2R2
We know that:
Volume of a sphere: 4/3πR^3
Volume of large sphere: 4/3πR1^3
Now we know that R1=2R2(given)
Thus volume of large sphere(V1) 32/3πR2^3.
Volume of small sphere(V2): 4/3πR2^3.
Ratio of volume of large sphere to small sphere is 8:1.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given the expression
3x + 2 = 4x + 5
1. The smaller coefficient of x is 3
to remove the smaller coefficient
we need to add - 3x to both sides
3x +2 + (-3x) = 4x +5 (-3x)
3x + 2 - 3x = 4x + 5 - 3x
Collecting like terms we have
3x-3x+2= 4x-3x+5
2 = x+ 5
2. The constant on the right side is
5,to remove the constant from the right side of the equation we need to add - 5 to both sides
3x + 2+ (- 5) = 4x + 5 +(-5)
3x+ 2-5 =4x +5-5
3x-3 = 4x
