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3 years ago

9 of 10

Mathematics

2 answers:

Ivenika [448]3 years ago

8 0

Answer:

$\frac{3}{10}$

Step-by-step explanation:

Set up the fraction 27/90
The numerator (the number above the fraction sign) represents the number of questions Jordan got correct.
The denominator (the number below the fraction sign) represents the number of questions on the test.
To simplify this equation, divide the numerator and denominator by their Greatest Common Factor (GCF) or continue dividing the numerator and denominator by the same number
GCF Method: GCF = 9 so 27/9 = 3 and 90/9 = 10
Therefore, the fraction is 3/10
Other Method: You know that 27 and 90 can be divided by 3, so divide both numbers by 3. 27/3 = 9 and 90/3 = 30.
9 and 30 can also be divided by 3. 9/3 = 3 and 30/3 = 10.
Therefore, the fraction is 3/10

Aleks04 [339]3 years ago

6 0

$\frac{3}{10}$

Answer:

Step-by-step explanation:

I just pressed 27/90 on the calculator hahahha

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Read 2 more answers

Find derivative problem<br> Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$