Answer:
4cotα=tanα
4(1/tanα)=tanα
(4/tanα)=tanα
cross multiply
=> 4=tan²α
√4=√tan²α
±2=tanα
α=arc( tan) |2|
α=63.4° ( in first quadrant)
and
α=180+63.4=243.4 in the third quadrant
since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)
α=180–63.4=116.6° in the second quadrant
α=360–63.4=296.6 in the fourth quadrant
therefore theta( in my case, alpha) lies in all four quadrants and is equal to:
α=63.4°,243.4°,116.6°and 296.6°
The new box will both hold more cereal and require more material to make.
Answer:
C
Step-by-step explanation:
By the definition of negative indices, we can rewrite our expression:
And by the definition of fraction powers, we can rewrite our term:
![\frac{1}{y^-^\frac{4}{3} }=\frac{1}{(\sqrt[3]{y})^4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7By%5E-%5E%5Cfrac%7B4%7D%7B3%7D%20%7D%3D%5Cfrac%7B1%7D%7B%28%5Csqrt%5B3%5D%7By%7D%29%5E4%7D)
Not sure if that's what C says because the picture is kinda blurry.
Answer:
Remove any grouping symbol such as brackets and parentheses by multiplying factors.
Use the exponent rule to remove grouping if the terms are containing exponents.
Combine the like terms by addition or subtraction.
Combine the constants.
Step-by-step explanation:
Using the identity a² - b² = (a + b) (a - b)
=> (3 {p - q})² - (5 {q - r})²
=> [(3 {p - q}) + (5 {q - r})] [(3 {p - q}) - (5 {q - r})]
=> [(3p - 3q) + (5q - 5r)] [(3p - 3q) - (5q - 5r)]
=> [3p - 3q + 5q - 5r] [3p - 3q - 5q + 5r]
=> [3p + 2q - 5r] [3p - 8q + 5r]
