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zzz [600]
2 years ago
12

I do not get any of this thing

Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
6 0
<h3>Answer:  C)  5/2</h3>

==========================================================

Explanation:

The term "zero" is the same as "root".

The root of f(x) is found by replacing f(x) with 0 and solving for x.

f(x) = 4x-20

0 = 4x-20

0+20 = 4x

20 = 4x

4x = 20

x = 20/4

x = 5

The root of f(x) is 5. If you plugged in x = 5, then you'll land on f(5) = 0.

Your teacher then wants to know what value of k will have g(x) get the same root of 5. In other words, we need to find k that will allow g(5) = 0.

We'll replace g(x) with 0 and plug in x = 5. Solving for k leads to...

g(x) = -0.5x+k

0 = -0.5*5+k

0 = -2.5+k

0+2.5 = k

2.5 = k

k = 2.5

k = 5/2

kobusy [5.1K]2 years ago
5 0

Answer:

C

Step-by-step explanation:

To find the zero of f(x) , let f(x) = 0 , that is

4x - 20 = 0 ( add 20 to both sides )

4x = 20 ( divide both sides by 4 )

x = 5 ← is the zero of f(x)

To find the zero of g(x) , let g(x) = 0 , that is

- \frac{1}{2} x + k = 0 ( multiply through by 2 to clear the fraction )

- x + 2k = 0 ( subtract 2k from both sides )

- x = - 2k ( multiply both sides by - 1 )

x = 2k ← is the zero of g(x)

Equating the 2 zeros

2k = 5 ( divide both sides by 2 )

k = \frac{5}{2} → C

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A where and a cylinder have the same radius and height . The volume of the cylinder is 48 cm 3. What is the volume of the sphere
SOVA2 [1]

Given:

Sphere and cylinder have same radius and height.

Volume of the cylinder = 48 cm³

To find:

The volume of the sphere.

Solution:

Radius and height of cylinder are equal.

⇒ r = h

Volume of cylinder:

V=\pi r^2h

Substitute the given values.

48=\pi r^2r   (since r = h)

48=\pi r^3

48=3.14 \times r^3

Divide by 3.14 on both sides.

$\frac{48}{3.14} =\frac{3.14\times r^3}{3.14}

$15.28=r^3

Taking cube root on both sides, we get

2.48 = r

The radius of the cylinder is 2.48 cm.

Sphere and cylinder have same radius and height.

Volume of sphere:

$V=\frac{4}{3} \pi r^3

$V=\frac{4}{3} \times 3.14 \times (2.48)^3

V=63.85

The volume of the sphere is 63.85 cm³.

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3 years ago
The average mass of an ant is approximately 3 × 10 − 3 grams. The average mass of a giraffe is approximately 2 × 10 3 kilograms.
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Given that average mass of an ant = 3 \times 10^{-3}grams.

Given that average mass of a giraffe = 2 \times 10^{3} Kilograms.

Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.

Like convert kilogram into gram or gram into kilogram.

I'm going to convert kilogram into gram using formula

1 Kg = 1000 g


So the average mass of a giraffe = 2 \times 10^{3} *10^3 grams.


Now we just need to divide mass of giraffe by mass of ant to find the answer.

\frac{2 \times 10^{3} *10^3 }{3 \times 10^{-3} }

= \frac{2 \times 10^{3} *10^3 *10^{3}}{3  }

= \frac{2 \times 10^{3+3+3}}{3  }

= \frac{2 \times 10^9}{3  }

= \frac{2}{3  } \times 10^9

=666666666.667

Hence final answer is \frac{2}{3  } \times 10^9 which is approx 666666666.667.

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Step-by-step explanation:

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