The large hose fills 1 pool in 9 hours written as 1/9
The small hose fills 1 pool in 18 hours, written as 1/18
Now you have 1/9 + 1/18 = 1/x ( x is the unknown time for both hoses).
rewrite 1/9 with a common denominator as 1/18:
1/9 = 2/18
Now you have 2/18 + 1/18 = 1/x
Add the left side:
2/18 + 1/18 = 3/18
Now you have 3/18 = 1/x
Cross Multiply:
3x = 18
Divide both sides by 3"
x = 18/3
X = 6
It will take both hoses 6 hours.
Step-by-step explanation:
P(t) = 12,000 (2)^(-t/15)
9,000 = 12,000 (2)^(-t/15)
0.75 = 2^(-t/15)
ln(0.75) = ln(2^(-t/15))
ln(0.75) = (-t/15) ln(2)
-15 ln(0.75) / ln(2) = t
t = 6.23