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saw5 [17]
3 years ago
7

Fill in the blank question.

Mathematics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

21 members

Step-by-step explanation:

We need to find 175% of 12. We can do this by multiplying 12 by 1.75. 12x1=12 and 12x0.75=9 and 12+9=21.

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State the domain and range of the following relation<br> x^2+y^2=16
Vlada [557]

The domain and range is  [-4, 4] and [0, 4]

<h3 /><h3>What is Domain and range?</h3>

The domain of a function is the set of values that we are allowed to plug into our function.

The range of a function is the set of values that the function assumes.

x² + y² = 16

y = √16 - x²

For domain under root should not be negative quantity,

16 - x²≥0

16≥x²

So, x≤4 or x≥4

Thus, the domain is  [-4, 4]

Range:

y is maximum at x=0, y=4

y is minimum at x=4, y=0

Thus, range = [0, 4]

Learn more about domain and range here:

brainly.com/question/12751831

#SPJ1

8 0
2 years ago
Work out the area of the trapezium.
Zanzabum

Answer:

58.29 cm²

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = \frac{1}{2} h (a + b) , substitute given values into formula

A = \frac{1}{2} × 6.7 × (7 + 10.4)

   = 3.35 × 17.4

   = 58.29 cm²

8 0
3 years ago
The length of the major axis of the ellipse below is 14, and the length of the
antiseptic1488 [7]

Answer:

11

Step-by-step explanation:

The focal length is 14, and thus the sum of the lengths of the blue and red segments is also 14.

8 0
2 years ago
A consumer group surveyed 146 airplane travelers after a flight and found that 132 of them would fly that airline again. Find th
prohojiy [21]

Answer:

\hat p =\frac{X}{n}

And replacing we got:

\hat p =\frac{132}{146}= 0.904

And for this case the standard error assuming normality would be given by:

SE= \sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

SE= \sqrt{\frac{0.904*(1-0.904)}{146}}= 0.024

Step-by-step explanation:

For this problem we know the following notation:

n= 146 represent the sample size selected

X= 132 represent the number of airplane travelers who after a flight  would fly that airline again

The estimated proportion for this case would be:

\hat p =\frac{X}{n}

And replacing we got:

\hat p =\frac{132}{146}= 0.904

And for this case the standard error assuming normality would be given by:

SE= \sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

SE= \sqrt{\frac{0.904*(1-0.904)}{146}}= 0.024

5 0
3 years ago
-8+ 8b = 16 8b+8=16 -8=-8 8b=8
e-lub [12.9K]

b = 3 \\ b = 1 \\ 0 \\ b = 1
7 0
4 years ago
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