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atroni [7]
2 years ago
6

BRAINIEST IF CORRECT

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
8 0

Answer:

The side of an equilateral triangle equals:

2 * height / sqr root (3)

side = 2 * sqr root (12) / sqr root (3)

side = 2 * 2 * sqr root (3) / sqr root (3)

side x = 4

Step-by-step explanation:

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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
please help me The question involves multiplying two complex numbers, then turning it into an a+bi equation (pictures included)
Sloan [31]

Answer:

  (a, b) = (0, -15)

Step-by-step explanation:

In "cis" form the product of two complex numbers is the product of their magnitudes at the angle that is the sum of their angles. I find this the easiest way to multiply complex numbers.

  z1 × z2 = (3 cis π)(5 cis π/2)

  = (3·5) cis (π +π/2)

  = 15 cis 3π/2

Of course, "cis" is short for "cosine + i·sine", so you have ...

  z1 × z2 = 15 cis 3π/2 = 15(cos(3π/2) +i·sin(3π/2))

  = 15(0 +i·(-1))

  = 0 -15i

(a, b) = (0, -15)

8 0
3 years ago
The necklace charm shown has two parts, each shaped like a trapezoid with identical dimensions.
Daniel [21]
What is the size of trapezoid?
3 0
3 years ago
Buying a car
____ [38]

Answer:

16,000

Step-by-step explanation:

20,000 x .20 = 4,000

20,000 - 4,000 = 16,000

7 0
4 years ago
Read 2 more answers
Suppose an experiment has 3 stages: A, B, and C. If stage A has 6 outcomes, stage B has 4 outcomes, and stage C has 3 outcomes.
zimovet [89]

Answer:

72

Step-by-step explanation:

Stage A has 6 outcomes, then B has 4 and C has 3

Take for example only 1 outcome of A, it will have 4 outcomes of B and each outcome of B will have 3 outcomes.

Then a single outcome of A has a total of 12 outcomes (4*3)

Writing it in a way A, B, C:

1,1,1

1,1,2

1,1,3

1,2,1

1,2,2

1,2,3

1,3,1

1,3,2

1,3,3

1,4,1

1,4,2

1,4,3

This is only taking in consideration 1 outcome of A, A has a total of 6 outcomes.

The total of outcomes in the experiment = 6*12=72

8 0
3 years ago
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