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3 years ago

2m - n =8 Solve for n

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

3 0

Answer:

$\boxed{\sf n = 2m - 8}$

Step-by-step explanation:

Solve for n:

⇒2m - n = 8

Subtract 2 m from both sides:

⇒2m - 2m - n = 8 - 2m

2m - 2m = 0:

⇒-n = 8 - 2 m

Multiply both sides by -1:

⇒-n × (-1) = (8 - 2m) × (-1)

⇒n = 2m - 8

nikitadnepr [17]3 years ago

3 0

Answer:

n=2m-8

Step-by-step explanation:

add n to both sides we have

2m-n+n=8+n

2m=8+n

carry 8 over to the other side we have

2m-8=n

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3 years ago

Rewrite the polynomial-9x^5+36x^4+189x^3 in factored form, using the factoring method method you prefer.

ozzi

The polynomial 9x^5+36x^4+189x^3 in factored form is $-9 x \times x \times x \times(x-7) \times(x+3)$

<u>Solution:</u>

Given, polynomial equation is $-9 x^{5}+36 x^{4}+189 x^{3}$

We have to find the factored form of the above given polynomial equation.

Let us solve it by grouping.

Now, take the polynomial ⇒ $-9 x^{5}+36 x^{4}+189 x^{3}$

By taking common term out, we get

$\rightarrow-9 x^{3}\left(x^{2}-4 x-21\right)$

$\rightarrow-9 x^{3}\left(x^{2}-(7-3) x-7 \times 3\right)$

Grouping the terms we get,

$\rightarrow-9 x^{3}\left(\left(x^{2}-7 x\right)+(3 x-7 x^3)\right)$

Taking common terms out from each group,

$\rightarrow-9 x^{3}(x(x-7)+3(x-7))$

$\Rightarrow-9 x^{3}((x-7)(x+3))$

$\rightarrow-9 x \times x \times x \times(x-7) \times(x+3)$

Thus the factored form of polynomial is found out

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