The distance of BF is 7.07
Answer:
e
f
∘
g
(
x
)
=
2
x
2
−
4
x
−
3
And
g
∘
f
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x
)
=
(
2
x
−
3
)
(
2
x
−
5
)
Step-by-step explanation: f
(
x
)
=
2
x
−
3
g
(
x
)
=
x
2
−
2
x
=
f
(
g
(
x
)
)
=
f
(
x
2
−
2
x
)
=
2
(
x
2
−
2
x
)
−
3
=
2
x
2
−
4
x
−
3
g
∘
f
(
x
)
=
g
(
f
(
x
)
)
=
g
(
2
x
−
3
)
=
(
2
x
−
3
)
2
−
2
(
2
x
−
3
)
=
(
2
x
−
3
)
(
2
x
−
3
−
2
)
=
(
2
x
−
3
)
(
2
x
−
5
)
f
∘
g
(
x
)
≠
g
∘
f
(
x
)
Answer:
I'd say none, as we're missing something in this problem. Make sure you've included everything to solve this problem. Thanks.
Answer: 
Step-by-step explanation:
Given : The fuel efficiency of car = 7.6 km per kilogram
We also given that
1 mile = 1.609 km
Then, 
1 gallon = 3.785 liters
1 liter of gasoline = 0.729 kg
Then, 
Now, the fuel efficiency of car will be :
Hence, the car’s fuel efficiency in miles per gallon= 4.5
Given : A = 24 sq feet
A = 0.5 base x height
base = x , height = x+2
A = 0.5 x(x+2) = 24 sq feet
1) 0.5 x(x+2) = 24 (A)
2) x^2 + 2x - 48 = 0 (D)
To check the rest un-wrap the bracket:
x^2 + (x+2)^2 = 24
x^2 + x^2 + 4 + 4x = 24
2x^2 + 4x - 20 = 0
x^2 + 2x - 10= 0 (NO)
Likewise:
x^2 + (x+2)^2 = 100
x^2 + x^2 +4 + 4x = 100
2x^2 + 4x + 4 = 100
2x^2 + 4x - 96 = 0
3) x^2 + 2x - 48 = 0 (F)
To sum up: that's what apply:
1) 0.5 x(x+2) = 24 (A)
2) x^2 + 2x - 48 = 0 (D)
3) x^2 + 2x - 48 = 0 (F)
