Answer: No idea, sorry. I'm sure you could look it up tho
Step-by-step explanation:
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Answer:
y= -7x+7
Step-by-step explanation:
y= mx+b
y= slope x+ y intercept
Well tan x has asymptotes every 90 degrees, or in radian mode, every pi divided by two. since cot is the inverse and the aymsptotes land on every 180 degrees, meaning the equation can be x ≠ \pi n, nEI
7(6) x 7(5) = 7(6+5) = 7(11) is the simplified answer.
Thank you!
