Answer:
g(f(x)) = -6x+6.
Step-by-step explanation:
It is given that,
f(x) = -3x + 2 and g(x) = 2x – 5
We need to find g(f(x)).
Put it into g(x).
g(f(x)) = 2(-3x + 2)+2
= -6x+4+2
=-6x+6
Hence, the value of g(f(x)) is -6x+6.
Answer:
yes i think
Step-by-step explanation:
The amount of different combos possible would be 165 // Hope this helped, comment below for any clarifications // Brainliest ;) Thanks!! //
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
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a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Answer:
There is needed around 311 balloons to fulfill Mr. Schordine’s dream of flight.
Step-by-step explanation:
First, we need to calculate the volume of each balloon by considering the balloons as a sphere:
Where:
r: is the radius = 0.4 meters
Knowing that 1 m³ of helium is able to lift about 1 kg, that Mr. Schordine weights 84 kg, and that each ballon has 0.27 m³ of helium, the number of balloons needed are:
Therefore, there is needed around 311 balloons to fulfill Mr. Schordine’s dream of flight.
I hope it helps you!
