Question

The ship left port at 0630 hr on 14 September and covered a distance of 1576 km to the first drill location (Site 1) where you are going retrieve a drill core of seafloor sediments. The ship arrived at the first drill site at 1800 hr on 16 September.
Calculate the rate of travel (i.e., speed) of the ship during its transit to the first drill site

Answer 1

Answer:

26.5 Km/h

Step-by-step explanation:

$Speed=\frac {distance}{time}$

The distance is given as 1576 Km

The time

From 14th Sept at 0630 to 16 September at 0630 that is equivalent to 48 hours

From 16th September at 0630 to 1800 that is 11.5 hours

Total time=48+11.5=59.5 hours

$Speed=\frac {1576 km}{59.5 hrs}=26.48739496 Km/h$

$Speed\approx 26.5 Km/h$