<span>1/2x+3y/4=5 => (1/2)x + (3/4)y = 5
1/5x+3y/2=2 => (1/5)x + (3/2)y = 2
Eliminate the fractional coefficients: Mult. the first equation by 4 and mult. the second equation by 10:
2x + 15y = 20
</span><span>Multiply the 1st equation by -1:
-</span>2x - 3y = -20
2x + 15y = 20
-------------------
12y = 0, so y = 0. Then the first equation becomes 2x + 3(0) = 20, or
x=10.
Solution is (10,0).
Answer:
I think its x=15
Step-by-step explanation:
Answer:
k < 3/7
Step-by-step explanation:
Step 1:Sinplify both sides of the inequality
10k <-4k+6
Step 2: Add 4k to both sides
10k + 4k < -4k + 6 + 4k
14k < 6
Step 3:Divide both sides by 14
14k/14 < 6/14
k <3/7
Note:Provided by Mathpapa an Algebra caculator
311,225,823,387,830,850,069
Oof
Answer:
b = - c + d - e
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