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yulyashka [42]
3 years ago
11

A store sells four printers for every five computers. The store sells 40 computers on Saturday. How many printers did it sell on

Saturday?
Mathematics
1 answer:
aleksley [76]3 years ago
3 0
32 printers were sold:
P:C
4:5
_:40
40/5=8
4x8=32

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(p_{10} = 58)

\frac{1}{10}\cdot \Sigma_{i=1}^{10} x_{i} = 58 (Eq. 1b)

Where x_{i} is the mark of the i-th boy, dimensionless.

In addition, we know the following mean marks from statement:

p_{7} = \frac{1}{7} \cdot \Sigma_{i = 1}^{7} x_{i} (Eq. 2)

(p_{7} = 61)

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p_{3} = \frac{1}{3}\cdot \Sigma_{i=8}^{10}x_{i} (Eq. 3)

Where:

p_{7} - Mean mark of the first 7 boys, dimensionless.

p_{3} - Mean mark of the remaining 3 boys, dimensionless.

By applying sum properties in (Eq. 1b) and using (Eq. 2b) and (Eq. 3), we obtain the mean of the remaining 3 boys:

\frac{1}{10}\cdot [\Sigma_{i = 1}^{7}x_{i}+\Sigma_{i=8}^{10}x_{i}] = 58

\frac{1}{10}\cdot [7\cdot (61)+3\cdot p_{3}] = 58

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3\cdot p_{3} = 153

p_{3} = \frac{153}{3}

p_{3} = 51

The mean of the remaining 3 boys is 51.

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