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3 years ago

Let f(x)=(x+2)^2

Mathematics

1 answer:

user100 [1]3 years ago

7 0

The graph if g(x) is vertically stretched by a factor of 3
Hope this helped :)

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Simplify: 6x^-2<br><br> a) 1/6x^2<br> b) 6/x^2<br> c) x^2/6<br> d) 1/36x^2

Salsk061 [2.6K]

Answer:

The correct answer choice is <u>option B. 6/x^2</u>

Step-by-step explanation:

8 0

3 years ago

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A shop owner offered a 20%discount off the regular price of a mirror.The amount of the discount is $3.00

Scrat [10]

Answer:

A) $15

Step-by-step explanation:

let x represent the regular price of the mirror

so, 20% of x = 3

20/100 * x = 3

20x = 300

x = 300/20

x = 15

Hence, the regular price of the mirror is $15

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3 years ago

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Consider the equation: 3 4 x − 12 = 12 Which statement could be a translation of the given equation? A number minus 12 is three-

musickatia [10]

Answer:

<h3>The translation statement for the given equation $\frac{3}{4}x-12=12$ is " Three-fourths of a number minus twelve is the same as twelve. "</h3>

Step-by-step explanation:

Given equation is $\frac{3}{4}x-12=12$

<h3>To find the statement which could be a translation of the given equation :</h3>

$\frac{3}{4}x-12=12$
The above equation can be written as
Three-fourths of a number x minus twelve is equal to twelve.

<h3>Therefore the translation statement for the given equation $\frac{3}{4}x-12=12$ is " Three-fourths of a number minus twelve is the same as twelve. "</h3>

The option is <u> " Three-fourths of a number minus twelve is the same as twelve. "</u> correct

4 0

4 years ago

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Find the sum of the first 10 terms if a(n) = n^2 - n +1

Elza [17]

Answer:

The formula to find the sum of the first n terms of our sequence is n divided by 2 times the sum of twice the beginning term, a, and the product of d, the common difference, and n minus 1. The n stands for the number of terms we are adding together.

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3 years ago

How do I do this and what’s the answers?

Iteru [2.4K]

Answer:

a.5years=300 rabbits

b. 50 years(multiply 50 by 300)

Step-by-step explanation:

hope this is helpful

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3 years ago