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tia_tia [17]
2 years ago
13

Carl is standing at the top of 35 Ft cliff looking down at a rock for motion in the sea. He estimates the angle of depression is

30' . What is the horizonal distance from Carl to the island?
Mathematics
1 answer:
Liula [17]2 years ago
7 0

The horizontal distance between Carl and the rock at sea is approximately 60.62ft.

Data;

  • Angle = 30 degree
  • Opposite = 35
  • Adjacent = x

<h3>Trigonometric Ratio</h3>

Given the angle of depression from his point to the sea, we can use trigonometric ratio to calculate for the horizontal distance from his location to the bottom of the sea.

SOHCAHTOA

Since we have the value of angle and opposite and we need to calculate the adjacent side of the right-angle triangle, we can use the tangent of the angle to this effect.

Tan\theta = \frac{opposite}{adjacent} \\tan 30 = \frac{35}{x}\\ x = \frac{35}{tan30}\\ x = 60.62ft

The horizontal distance between Carl and the rock at sea is approximately 60.62ft.

Learn more on trigonometric ratio here;

brainly.com/question/12172664

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Tony needs to create a platform shaped like the diagram with the labeled dimensions.
konstantin123 [22]
<h2>135 cubic feet of concrete are required to create the platform.</h2>

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Therefore concrete are required to make lower step = (6×3×1.5) cubic feet

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For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?
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The values of x for which the given vectors are basis for R³ is:

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We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

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The matrix formed by these vectors is:

\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]

Now, the determinant of this matrix is:

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-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1

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