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3 years ago

1/4 Marks

Mathematics

2 answers:

Reptile [31]3 years ago

7 0

A= 24.58
B= 562.68
C=58.99
D= 0.98

rusak2 [61]3 years ago

3 0

Answer:

rounded the following given numbers below

Step-by-step explanation:

a) 24.58

b) 562.68

c) 58.99

d) 0.98

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A home improvement store normally sells 20-foot extension ladders for $225. This week the ladders are discounted by 20%. What is

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Answer:

The answer is 180

Step-by-step explanation:

So to start off you have to turn 20% into a decimal and that is .20.

Next you need to mutiply 225 and .20 and you will get 45 (that means it is $45 off)

Subtract 45 fro 225 and that is your answer.

You now pay $180 for the 20 foot extension ladder.

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3 years ago

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On a vacation in Puerto Rico rose jumped off a cliff into a river in El Yunque go forest reserve her height as a function of tim

gayaneshka [121]

Answer: t = 6 s

Step-by-step explanation:

When Rose hit the water, the height of the jump is 0, so: h(t) = 0.

Resolving it, we have:

-16t² + 16t + 480 = 0

To simplify the second degree equation, divided it by 16:

-t² + t + 30 = 0

Now, solve the equation using Bhaskara:

Δ = 1² - 4. (-1) . 30

Δ = 1 + 120

Δ = 121

t = $\frac{-1+\sqrt{121} }{-2}$

t₁ = $\frac{-1 + 11}{-2}$ = - 5

t₂ = $\frac{-11-11}{-2}$ = 6

Since time can be negative, it took t = 6s for Rose to hit the water.

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3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

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3 years ago