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Reptile [31]
3 years ago
6

Ernest the Elf likes to stay in shape all year. He runs 4.65 miles each day. How many miles has he completed after 3 weeks?

Mathematics
1 answer:
professor190 [17]3 years ago
3 0

Answer:

97.65 miles

Step-by-step explanation:

4.65 times the 21 days

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Hannah notices that segment HI and segment KL are congruent in the image below: Two triangles are shown, GHI and JKL. G is at ne
BlackZzzverrR [31]

Answer:

segment IG ≅ segment LJ

Step-by-step explanation:

Please refer to the attached image as per the triangles as given in the question statement.

\triangle HGI, \triangle JKL

G\left(-3,1\right),\ H\left(-1,1\right),\ I\left(-2,3\right)

J\left(3,3\right),K\left(1,3\right),L\left(2,1\right)

Given that:

HI\cong KL and

\angle I \cong \angle L

<em>SAS congruence </em>between two triangles states that two triangles are congruent if two corresponding sides and the angle between the two sides are congruent.

We are given that one angle and one sides are congruent in the given triangles.

We need to prove that other sides that makes this angle are also congruent.

To show the triangles are congruent i.e. \triangle GHI \cong \triangle JKL by SAS congruence we need to prove that

segment IG ≅ segment LJ

Let us use Distance formula  to find IG and LJ:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

IG  =\sqrt{(-2+3)^2+(3-1)^2} =\sqrt5\ units

LJ  =\sqrt{(2-3)^2+(1-3)^2} =\sqrt5\ units

Hence, segment IG ≅ segment LJ

\therefore ΔGHI ≅ ΔJKL by SAS

4 0
3 years ago
Sue played the same computer game.
pantera1 [17]
30? Cause I take 12 times 0.4
5 0
3 years ago
Test
Doss [256]

Answer:

hsहसगवस सकगस ाजसगह

Step-by-step explanation:

हसजडगकोसकहड सका सकसद ौजह

3 0
3 years ago
Please help me ASAP!!!
Anna71 [15]

by triangle angle addition law

a + b + c = 180

3x +1 + 2x-1 +40 = 180

5x +40 = 180

5x = 180 - 40 = 140

x = 140/5 = 28

so

b = 2x -1 = 2×28-1= 56-1 = 55

4 0
3 years ago
Please help ill mark brainliest!!!
Bingel [31]

Triangle QST  is similar to triangle PQR

We are given that measure of angle SRP is 90°

Q is the point of the hypotenuse SP

Segment QR is perpendicular to PS and T is a point outside the triangle on the left of s

We need to find which triangle is similar to triangle PQR

So,

Using Angle - Angle - Angle Criterion We can say that

m∠PQR = m∠SQR  (AAA similarity)

m∠SQR=m∠SQT (AAA similarity)

Where m∠Q =90°  in ΔQST and PQR

Therefore ΔQST is similar to ΔPQR

Learn more about similarity of triangles here

brainly.com/question/24184322

#SPJ4

8 0
2 years ago
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