Answer:
LM = LO
Explanation: In order to use the HL Theorem the triangles included must be right triangles and in this case they must have a congruent hypotenuse and in order for that, LM must be congruent to LO.
Answer:
The list of angles of the triangle in order from smallest to largest will be: A < C < B
Hence, option 'e' is true.
i.e (A,C,B)
Step-by-step explanation:
We know that in a triangle the greater angle has the longer side opposite to it.
From the given triangle,
Side AC = 7.2 is the longer side. Thus, B is the largest angle as it is opposite to the longer side AC = 7.2.
Then comes the second-longest side AB=4.9. Thus, C is the 2nd largest angle it is opposite to the second-longest side AB=4.9.
Finally comes the shortest side BC = 3.2. Thus, A is the shortest angle as it is opposite to the shortest side BC = 3.2.
Thus, the list of angles of the triangle in order from smallest to largest will be: A < C < B
Hence, option 'e' is true.
i.e (A,C,B)
Answer:
f(x) is a one to one function.That maps out one function to another ,and it therefore passes both the vertical and horizontal I ine test
<span>when p = -24 and q = 4. p/2q= -24/8 = -3 </span>
Answer:
I'm going to paint you a picture in words of what this looks like on paper. We have a train leaving from a point on your paper heading straight west. We have another train leaving from the same point on your paper heading straight east. This is the "opposite directions" that your problem gives you.
Now let's make a table:
distance = rate * time
Train 1
Train 2
We will fill in this table from the info in the problem then refer back to our drawing. It says that one train is traveling 12 mph faster than the other train. We don't know how fast "the other train" is going, so let's call that rate r. If the first train is travelin 12 mph faster, that rate is r + 12. Let's put that into the table
distance = rate * time
Train 1 r
Train 2 (r + 12)
Then it says "after 2 hours", so the time for both trains is 2 hours:
distance = rate * time
Train 1 r * 2
Train 2 (r + 12) * 2
Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r. The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24. The distance between them (which is also the length of the whole entire arrow) is 232. Thus:
2r + 2r + 24 = 232 and
4r = 208 so
r = 52
This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph
Step-by-step explanation:
