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poizon [28]
3 years ago
6

Find the slope of (-3,1)(4, -3)

Mathematics
2 answers:
e-lub [12.9K]3 years ago
8 0

The slope is -4/7

Step-by-step explanation: The equation for slope is (y₂-y₁)/(x₂-x₁)

so in this case it would be (₋3-1)/(4+3)

Ratling [72]3 years ago
7 0

Finding the slope using two points:

The formula for slope is

\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

In this case...

y_{2} =-3\\y_{1} =1\\x_{2} =4\\x_{1} =-3

^^^Plug these numbers into the formula for slope...

\frac{-3-1}{4 - (-3)}

\frac{-4}{7}

^^^This is your slope

Hope this helped!

~Just a girl in love with Shawn Mendes

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Solve for X then find the measure of
Savatey [412]

Answer:

x=11

m<a=80º

m<b=80º

Step-by-step explanation:

They are congruent so

8x-8=5x+25

8x=5x+33

3x=33

x=11

6 0
3 years ago
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What is 3+2-8+9+8+0-6-9+8
monitta

Answer:

7

Step-by-step explanation:

First,

3+2=5

5-8=-3

-3+9=6

6+8=14

14+0=14

14-6=8

8-9=-1

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8 0
3 years ago
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point
kiruha [24]
This is going to be an long answer, so I'm putting the answer first. y=3x-7

First, you have to find the equation of the line given. You can use point slope form for that. You can see that the slope is -1/3, and it goes through (2,2). So, the equation would be
y-2=-1/3(x-2)
Which simplifies to
y=-1/3x+8/3

Now, we can get on to finding the actual answer. The slope of a line perpendicular would be the negative reciprocal of the original slope. That just means you flip it and multiply it by -1. So, the slope of the new line is 3. Now you can use point slope form again and make an equation, which is
y+1=3(x-2)
Which simplifies to
y=3x-7

Please don't ask me why the slope is the negative reciprocal, or how they came up with the formula for the point slope form. I DON'T KNOW. If you want to know so bad you would give up chick-fil-A for the rest of your life, there's always google.
5 0
3 years ago
Read 2 more answers
In order to construct a line parallel to line m through a given point, P. you first
riadik2000 [5.3K]

Answer:

90 degree angles (perpendicular bisector of the line)

4 0
3 years ago
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