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seropon [69]
3 years ago
12

Find the missing value when given the modulus. 2. (picture) (in the third quadrant)

Mathematics
2 answers:
Nat2105 [25]3 years ago
5 0

Answer:

The value of a is -6.

Step-by-step explanation:

A complex number is defined as

z=x+iy

|z|=|x+iy|=\sqrt{x^2+y^2}

where, x is real part and iy is imaginary part.

The given equation is

|a-i|=\sqrt{37}

Here real part is a and imaginary part is -i. So, x=a and y=-1.

\sqrt{a^2+(-1)^2}=\sqrt{37}

Taking square on both the sides.

a^2+(-1)^2=37

a^2+1=37

Subtract 1 from both the sides.

a^2=36

Taking square root on both the sides.

a=\pm \sqrt{36}

a=\pm 6

The value of a is either 6 or -6. But it is given that the picture is in third quadrant, so the value of a can not be positive.

Therefore the value of a is -6.

wolverine [178]3 years ago
4 0
Hello, Kana back on for some more questions! :3
let's see what you have now...
what are these questions ._. ...I can't understand hmmm...

Firstly, do you know what the | a - i | stands for? and are you trying to divide?
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Suppose that 1 kg of Sodium-24 is reduced to 0.0156 kg in 90 hours. What is the half-life, in hours, of Sodium-24?​
N76 [4]

Answer:

14.99 hours

Step-by-step explanation:

The formula for half-life is given as,

R/R' = 2ᵃ/ᵇ...................... Equation 1

Where R= Original mass of sodium-24, R' = mass of Sodium-24 after disintegration, a = Total time taken for sodium-24 to disintegrate, b = half-life of sodiun-24.

Given: R = 1 kg, R' = 0.0156 kg, a = 90 hours

Substitute into equation 1 and solve for b

1/(0.0156) = 2⁹⁰/ᵇ

Taking the log of both side

log[1/(0.0156)] = log(2⁹⁰/ᵇ)

log[1/(0.0156)] = 90/b(log2)

90/b = log[1/(0.0156)]/log2

90/b = 6.0023

b = 90/6.0023

b =  14.99 hours

b = 14.99 hours.

Hence the half-life of Sodium-24 is 14.99 hours

7 0
3 years ago
Joshua places the letters in the word SNOWMAN in a bag. A letter is drawn randomly and not replaced. Then another letter is sele
oksano4ka [1.4K]

Answer:

13/42

Step-by-step explanation:

1/7 + 1/6

13/42

7 0
2 years ago
PLEASE HELP ME WITH THIS PROBLEM AND EXPLAIN HOW YOU GOT THE ANSWER!?!?
Advocard [28]
4:10 pm ....................................
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3 years ago
The graph shows the number of laps that Jan runs as her coach times her.
fenix001 [56]
Four laps every two minutes. look down from the slope. thats tje tome or minutes and if you look to the left thats how many laps.
5 0
3 years ago
Q18. The sum of the first N terms of an arithmetic series, S, is 292 The 2nd term of S is 8.5 The 5th term of Sis 13 Find the va
Gelneren [198K]

Step-by-step explanation:

Sn= a+[n-1]d

S2= a+[2-1]d

8.5 = a+d _______Equation 1

S5 = a+[5-1]d

13=a+4d ________Equation 2

Subtract Equation 1 from Equation 2

13=a+4d

-

8.5= a+d

________

4.5= 3d

d=1.5

Substituting d=1.5 in equation 1

8.5=a+1.5

a=8.5-1.5

a=7

Sum of terms of an A.P =

Sn= n/2[2a+(n-1)d]

292= n/2[2×7+(n-1)d]

292=n/2[14+(n-1)1.5

292×2=n[14+(n-1)1.5]

584=n[14+1.5n-1.5]

584= 14n+1.5n²-1.5n

584= 1.5n²+12.5n

1.5n²+12.5n-584

1.5n²-24n+36.5n-584

1.5n(n-16)+36.5(n-16)

(1.5n+36.5)(n-16)

**n-16=0

n=16

3 0
1 year ago
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