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2 years ago

50 Points!!! PLEASE HELP!

Mathematics

1 answer:

Ymorist [56]2 years ago

5 0

Answer:

its c and its right

Step-by-step explanation:

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Math matrix with variable

masya89 [10]

AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA S

]AS]

L.ASDAA

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AAAAAAA

]]]]]AASSSSSSSSSSSSSSAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

8 0

3 years ago

Kevin wants to paint the box with a new color. He must determine the surface area of the box to caculate the amount of paint to

tankabanditka [31]

Answer:

Whatever he wants, he's painting so he can paint however he wants

7 0

3 years ago

Read 2 more answers

Due Today, Please help me.

Vsevolod [243]

Answer:

Yes, SAS.

Step-by-step explanation:

For my education system, there isn't such thing as SAS, ASA or etc. I just had to search it up what it was.

Congruent angles are angles with the same shape and size. The two triangles are congruent if you look carefully, after that I searched up and saw the different rules of triangles. I think that SAS might be the correct answer.

6 0

2 years ago

Calculate the specific heat of a metal (in calories/gram-degree C) from the following data. A container made of the metal has a

Arisa [49]

Answer:

<h2>The specific heat of the metal is 0.274951 calories/gram-degree C.</h2>

Step-by-step explanation:

Let, the specific heat of the container is x calories/gram-degree C.

The container and water gains (18 - 15) = 3 degrees C.

Hence, the transfer of heat is $3(18.1\times1000\times1) + 3(3.77x\times1000)$ .

The metal, which is dropped in the water, losses (164 - 18)= 144 degrees C.

Hence, the transfer of heat is $144\times 1.45\times1000x$ .

As per the given conditions,

$3(18.1\times1000) + 3(3.77x\times1000) = 144\times1.45\times1000x\\54.3 + 11.31x = 208.8x\\197.49x = 54.3\\x = 0.274951$ .

6 0

3 years ago

Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor

docker41 [41]

Given:

The table of values is

Number of Students : 7 14 21 28

Number of Textbooks : 35 70 105 140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

$\dfrac{35}{7}=5$

$\dfrac{70}{14}=5$

$\dfrac{105}{21}=5$

$\dfrac{140}{28}=5$

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

$\dfrac{y}{x}=k$

Here, k=5.

$\dfrac{y}{x}=5$

$y=5x$

Hence the rate of change is constant that is 5.

8 0

3 years ago