Question

The following balanced equation shows the decomposition of ammonia (NH3) into nitrogen (N2) and hydrogen (H2). 2NH3 → N2 3H2 A quantity of NH3 decomposes to produce 0. 0351 mol N2. How many moles of H2 are produced? 0. 0351 mol H2 0. 0117 mol H2 0. 105 mol H2.

Answer 1

The moles of hydrogen produced in the reaction has been 0.105 mol. Hence, option D is correct.

The balanced chemical equation for the decomposition of Ammonia has been:

$\rm 2\;NH_3\;\rightarrow\;N_2\;+\;3\;H_2$

Computation for moles of Hydrogen produced

From the balanced chemical equation, decomposition of 2 moles of ammonia produces, 3 moles of hydrogen and 1 mole, nitrogen.

The moles of hydrogen produced along with 0.0351 mol nitrogen has been:

$\rm 1\;mol\;N_2=3\;mol\;H_2\\ 0.0351\;mol\;N_2=0.0351\;\times\;3\;mol\;H_2\\ 0.0351\;mol\;N_2=0.105\;mol\;H_2$

Thus, the moles of hydrogen produced in the reaction has been 0.105 mol. Hence, option D is correct.

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