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weqwewe [10]
3 years ago
10

4. You have a very concentrated solution (12 M) of potassium chloride (KCI). You need it to be at the least concentration possib

le for the experiment you are
about to conduct. The problem is you forgot to order lab supplies, so you only have 2 L of distilled water left. What would be the final concentration if you
added the two 2 L of distilled water to the 0.5 L of 12 M KCI?
a 3.0 M
b 24 M
C 2.4M
d 48 M
Chemistry
1 answer:
Alenkinab [10]3 years ago
4 0

Answer:

C. 2.4 M

Explanation:

Because you started with 12M solution of KCl, that means that there was a concentration of 12 mols of KCl per Liter of solution. (12mol/1L =12 M). Since there was only 0.5L of solution, there was only 6 mols of KCl because there is only 12 mols per 1 Liter, so half of that volume would have half the amount of solute to keep that true. (6mol/.5L = 12 M). With the new water added, the formula becomes (6mols KCl/ 2.5L of water =2.4 M)

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For the galvanic (voltaic) cell Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s) (E°= 0.77 V at 25°C), what is [Fe2+] if [Mn2+] = 0.040 M and
avanturin [10]

Answer:

0.01836 M

Explanation:

Again the reaction equation is;

Fe(s) + Mn2+(aq) → Fe2+(aq) + Mn(s)

E°cell= 0.77 V

Ecell= 0.78 V

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[Fe2+] = the unknown

n=2

From Nernst's equation;

Ecell= E°cell- 0.0592/n log Q

0.78= 0.77 - 0.0592/2 log [Fe2+] /[0.040]

0.78-0.77= - 0.0592/2 log [Fe2+] /[0.040]

0.01/ -0.0296= log [Fe2+] /[0.040]

-0.3378= log [Fe2+] /[0.040]

Antilog(-0.3378) = [Fe2+] /[0.040]

0.459= [Fe2+] /[0.040]

[Fe2+] = 0.459 × 0.040

[Fe2+] = 0.01836 M

7 0
3 years ago
Ethanol (C2H5OH) and water (H2O) are both liquids at or near room temperature. When a sample of ethanol is poured into a beaker
BaLLatris [955]

Answer:

a. Are miscible because each can hydrogen bond with the other.

Explanation:

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5 0
3 years ago
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The d subshell has 5 orbitals (with each being able to hold two electrons.  As such, the d orbital can hold a maximum of 10 electrons.

<span>The "d" subshell can hold a maximum of _TEN_ electrons.</span>
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3 years ago
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Answer:

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3 years ago
What are the oxidation numbers of K, Cl, and O in KClO,?
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Answer: Oxidation number of chlorine in potassium chlorate...

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Explanation: hope this help

4 0
3 years ago
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