How do you verify inverses algebraically?

Mathematics

1 answer:

Slav-nsk [51]2 years ago

3 0

Answer:

Let f be a function. If any horizontal line intersects the graph of f more than once, then f does not have an inverse. If no horizontal line intersects the graph of f more than once, then f does have an inverse.

Step-by-step explanation:

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Find the missing term. If y = 1 + i, then y3 − 3y2 + ( ? ) − 1 = -i .

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$y=1+i\qquad\qquad i^2=-1\\\\\\
y^3-3y^2+(?)-1 =-i\\\\(1+i)^3-3\cdot(1+i)^2+(?)-1+i=0\\\\1^3+3i+3i^2+i^3-3\cdot(1^2+2i+i^2)+(?)-1+i=0\\\\
1+3i+3\cdot(-1)+i\cdot i^2-3-6i-3i^2+(?)-1+i=0\\\\
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3 years ago

Read 2 more answers

What is the measure of angle VYZ

irakobra [83]

Answer:

$\boxed{\sf C. \ 161 ^{ \circ}}$

Step-by-step explanation:

<em>Opposite angles are also congruent angles, meaning they are equal or have the same measurement.</em>

$\sf \implies \angle VYZ = \angle WYT \\ \\ \sf \implies(8x + 1) ^{ \circ} = (9x - 19)^{ \circ} \\ \\ \sf \implies 8x^{ \circ} + 1^{ \circ} = 9x^{ \circ} - 19^{ \circ} \\ \\ \sf \implies 8x^{ \circ} - 9x^{ \circ} + 1^{ \circ} = - 19^{ \circ} \\ \\ \sf \implies - x^{ \circ} = - 19^{ \circ} - 1^{ \circ} \\ \\ \sf \implies \cancel{ -} x^{ \circ} = \cancel{- }20^{ \circ} \\ \\ \sf \implies x^{ \circ} = 20^{ \circ}$

$\therefore$

$\sf \implies \angle VYZ =(8x + 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =(8 \times 20 + 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =( 160+ 1) ^{ \circ} \\ \\ \sf \implies \angle VYZ =161 ^{ \circ}$