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Jobisdone [24]
3 years ago
14

2x^2+x-6=0 find the complex roots

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0
2x²+x-6=0
(2x-3)(x+2)=0
x=3/2 or -2
☺☺☺☺
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As a decimal your answer: is 5.4 rounded to the nearest tenth. As a mixed number fraction your answer is: 5 11/25. As a improper fraction your answer is: 136/25.

Step-by-step explanation:

Basically what I did was just divide 6.8 by 4/5. Or you could change 4/5 in a decimal and divide like that, OR change 6.8 into a fraction which is what if did- I’ll show you below. But, it’s better to have all solutions to the problem.

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B. Decimal: 5.44 or 5.4 rounded to nearest tenth.

I hope this helped, good luck! :)

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