Hey there! I'm happy to help!
First, let's find the area of the top of the bar.
30×70=2100
This is the same as the bottom of the bar, so we have another 2100 mm, giving us 4200 in total.
Now we want to find the two long sides. This is 70×4.5, which is 315. Since there are two of these sides, we have another 315, giving us 630 in total there.
Now we have the short sides.
30×4.5=135
135×2=270
Now, we add up all of these measurements.
4200+630+270=5100
Therefore, Will's Wrapping Company will need 5100 mm² of paper to make their wrapper.
Have a wonderful day! :D
Step-by-step explanation:
b) y=x+1
table:
_x _|_2x_|_y_|(x, y)|
0 |2(0) |1 |(0, 1)|
1 | 2(1) |2 |(1, 2)|
2 | 2(2) |3 |(2, 3)|
3 | 2(3) |4 |(3, 4)|
c) y=3x+2
_x _|_2x_|_y_|(x, y)|
0 |2(0) |2 |(0, 2)|
1 | 2(1) |5 |(1, 5)|
2 | 2(2) |8 |(2, 8)|
3 | 2(3) |14 |(3, 14)|
To graph, plot the x, y points and connect all of them
Answer:
2
Step-by-step explanation:
<em>for </em><em>this </em><em>question</em><em> </em><em>you've </em><em>to </em><em>cross </em><em>multiply</em>
<em>-</em><em>2</em><em>2</em><em>/</em><em>9</em><em>r</em><em>=</em><em>1</em><em>1</em><em>/</em><em>9</em>
<em>9</em><em>9</em><em>r</em><em>=</em><em>-</em><em>1</em><em>9</em><em>8</em>
<em>then </em><em>you </em><em>divide</em><em> both</em><em> sides</em><em> by</em><em> </em><em>9</em><em>9</em><em> </em><em>inorder </em><em>to </em><em>remain </em><em>with </em><em>r </em><em>on </em><em>one </em><em>side</em>
<em>9</em><em>9</em><em>r</em><em>/</em><em>9</em><em>9</em><em>=</em><em>1</em><em>9</em><em>8</em><em>/</em><em>9</em><em>9</em>
<em>r=</em><em>2</em>
<em>I </em><em>hope </em><em>this </em><em>helps</em>
You’d be going 70 miles every hour
Answer:
The rate of change of the area of the circle is approximately
.
Step-by-step explanation:
Given:

radius 
We need to find the rate of change of the area of the circle at that instant.
Solution:
Now we know that;
Area of the circle is given by π times square of the radius.
framing in equation form we get;

to find the rate of change of the area of the circle at that instant we need to take the derivative on both side.

Substituting the given values we get;

Hence The rate of change of the area of the circle is approximately
.