<span>(3x^2+3)(4+x^3)
=</span><span>12x^2 +3x^5 + 12 + 3x^3
= </span>3x^5 + 3x^3 + 12x^2 + 12
Answer:
13,784
Step-by-step explanation:
The given equation is: 
To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.
The equation to a line perpendicular to it is:
$ 2y-x=c$
where, $c$ is some constant we have determine using the condition given.
It passes through $(2,-1)$
Put the point in our equation:
$2(-1)-(2)=c$
$c=-2-2$
$c=-4$
The final equation is:
$\boxed{ 2y-x=-4}$
Amount financed
320−100=220
Total paid
100+25×12=400
Interest paid
400−320=80
Interest rate=(2yc)÷(m (n+1))
I=(2×12×80)÷(220 (12+1))
I=(2×12×80)÷(220×13)
I=0.67×100
I=67%