Answer:
EF = 6.6
Step-by-step explanation:
Since ABCD is similar to EFGH, then EH is similar to AD. So, we can solve by first dividing 12 by 2 (EH by AD). The quotient of this is 6. This tells us that quadrilateral EFGH is 6 times larger than quadrilateral ABCD, since they are similar. So, with this and the measurement of AB (which is similar to EF), we can now solve for EF. We simply multiply 1.1 (the measurement of AB) by 6 (how many times larger EFGH is compared to ABCD). The product of this is 6.6, our final answer.
Answer:
x²(9x– 11)(9x + 11)
Step-by-step explanation:
81x⁴ – 121x²
The expression can be factorised as follow:
81x⁴ – 121x²
x² is common to both term. Thus:
81x⁴ – 121x² = x²(81x² – 121)
Recall:
81 = 9²
121 = 11²
Therefore,
x²(81x² – 121) = x²(9²x² – 11²)
= x²[(9x)² – 11²]
Difference of two squares
x²(9x– 11)(9x + 11)
Therefore,
81x⁴ – 121x² = x²(9x– 11)(9x + 11)
Answer:
8im thinking
Step-by-step explanation:
but is ae the x?
The answer should be D
Step by Step: |2x-2| <(or equal to) 6
Add 2 on both sides should give you, |2x| < 8
Divide both sides by 2, giving you 4
Other way, is doing the same but -2
Answer:
no of kernels pop = 4.34
Step-by-step explanation:
given data
kernels pop in 5 second = 12
kernels are present = 235
solution
we get here kernels are pop at rate of here
kernels are pop at rate = 12 ÷ 235
kernels are pop at rate = 0.051063
and
we get here maximum kernels are remaining that is
maximum kernels remaining = 235 - 140
maximum kernels remaining = 85
so
no of kernels pop in 5 second will be
no of kernels pop = 0.051063 × 85
no of kernels pop = 4.34
