Answer:
a. 84 < n + (n + 2) + (n + 4) < 96
b. 26 < n < 30
Step-by-step explanation:
Let n = 1st number
n+2 2nd even number
n+4 = 3rd even number
The sum of these 3 numbers is
n+n+2+n+4
It must be between 84 and 96 (it does not include this 84 and 96)
84< n+n+2+n+4 < 96
Now we need to solve this
Combine like terms
84 < 3n +6< 96
Subtract 6 from all sides
84 -6 < 3n+6-6 < 96 -6
78 < 3n < 90
Divide all sides by 3
78/3 < 3n/3 < 90/3
26 < n< 30
Answer:
23/8
Step-by-step explanation:
Answer:
(8 - 12 )
Step-by-step explanation:
Given
x -
y = 8
x +
y = - 5
Multiply both equations through by 4 to clear the fractions
x - 2y = 32 → (1)
2x + 3y = - 20 → (2)
Multiplying (1) by - 2 and adding to (2) will eliminate the x- term
- 2x + 4y = - 64 → (3)
Add (2) and (3) term by term to eliminate x
0 + 7y = - 84
7y = - 84 ( divide both sides by 7 )
y = - 12
Substitute y = - 12 into either of the 2 equations and solve for x
Substituting into (1)
x - 2(- 12) = 32
x + 24 = 32 ( subtract 24 from both sides )
x = 8
solution is (8, - 12 )
The answer is c, because it is the same line, just higher.