Given sides of length 300 mm or 190 mm, you can form 4 different triangles:
- equilateral with sides 190 mm
- equilateral with sides 300 mm
- isosceles with two sides 190 mm and one side 300 mm
- isosceles with two sides 300 mm and one side 190 mm
The triangle inequality requires the sum of the lengths of any two sides be not less than the length of the third side. Since 2×190 > 300, you can mix and match these side lengths any way you want. With three sides and 2 choices for each, there are only a limited number of possibilities.
In the above, we have not listed ones that are simply rotations or reflections of a congruent triangle. (A 190-190-300 triangle looks the same as a 190-300-190 triangle, for example.)
Answer:
The relation 
is explained below.
Step-by-step explanation:
P(x, y) is a point on the circle. Q is the origin. Join PQ.
PQ is the radius.
Therefore, PQ = r
Draw PS perpendicular to the x-axis.
Now, ΔPQS is a right triangle.
By Pythagoros theorem,
Answer:
-1.75.
Step-by-step explanation:
The z-score = (n - m) / d where n is the value (13) m = mean and d = standard deviation.
= (13 - 20) / 4
= -1.75 (answer)
Answer:
363
Step-by-step explanation:
Formula for area of a circle
A = πr^2
Where r = radius
The circle has a given radius of 11
To find the area of the circle we simply substitute r in the formula with the value of the radius (11)
( Also note that the question says to use 3 for π )
A = πr^2
π = 3
r = 11
Substitute values in formula
A = (3)(11)^2
11^2 = 121
A = 121(3)
121(3) = 363
A = 363
Answer:I think that it would be either b or c
Step-by-step explanation:
