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borishaifa [10]
3 years ago
10

a proportional relationship is represented on a graph with a line that had a slope of 65. what is the unit rate of the relations

hip?
Mathematics
1 answer:
erik [133]3 years ago
8 0

Answer:

65

Step-by-step explanation:

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01-1-
klio [65]

Answer:

Step-by-step explanation:

50 dollars = ∉34

∉1 = Rs 150

Rs 382800 / 150 Rs per ∉  =  382800/150 ∉

=2552 ∉

50 dollars = ∉34          so 50/34 dollars = ∉

2552 ∉ × 50/34 dollar per ∉ =       in the units the ∉ cancel out

                                                         ∉ × dollar/∉    = dollars

(2552 × 50) / 34    = 3752.94 dollars     <------------------

Here is another way of looking at the answer...........

Rs 382800 × 1∉/150 Rs × 50 dollars/34 ∉ =              note how the units cancel

= 382800 × (1/150) × (50/34)                          Rs × ∉/Rs × dollars/∉

=  3,752.94 dollars                                     leaving only dollars in the numerator

7 0
3 years ago
Brian wants to build a ramp that leads to a storeroom 5 meters above the ground. He wants the ramp to be 10 meters long. What sh
Kamila [148]
You should have an angle of elevation of 30 degrees.
6 0
3 years ago
Read 2 more answers
Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra
Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize x^2-\frac13 as yet another difference of squares:

x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)

And if you're working over the field of complex numbers, you can go even further. For instance,

x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)

But I think you'd be fine stopping at the first result,

x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}

6 0
3 years ago
I need help with this pls
shtirl [24]

Answer:5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Simplify: 8x + 3 +6x-5
Sphinxa [80]

Answer:

14x +2

Step-by-step explanation:

(8x + 6x) +3 -5 = (14x) +3-5

14x (+ 3-5) = 14x (+ 2)

6 0
3 years ago
Read 2 more answers
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