2 1/5 x 3 1/2 as fraction
1 answer:
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7,912.8 inch³ of aluminum is needed to make 70 metal balls.
Step-by-step explanation:
Step 1:
The area of a sphere is calculated by multiplying with π and the cube of the radius (r³).
In the given problem, the diameter is 6 inches. So the radius of the spheres is 3 inches.
The volume of a sphere,
So if r = 3 inches and π = 3.14,
cubic inches.
So for a single aluminum ball, 113.04 inch³ of aluminum is needed.
Step 2:
If 113.04 inch³ of aluminum is used for 1 ball, then we multiply 70 with this value to determine the aluminum needed for 70 such balls.
The aluminum needed for 70 metal balls inch³.
So 7,912.8 inch³ of aluminum is needed to make 70 metal balls.