The answer is b because are congruent
The two linear equations in two variable is:
12 x + 3 y = 40
7 x - 4 y = 38
(a) For a system of equations in two Variable
a x + by = c
p x + q y = r
It will have unique solution , when

As, you can see that in the two equation Provided above

So, we can say the system of equation given here has unique solution.
(b). If point (2.5, -3.4) satisfies both the equations, then it will be solution of the system of equation, otherwise not.
1. 12 x+3 y=40
2. 7 x-4 y=38
Substituting , x= 2.5 , and y= -3.4 in equation (1) and (2),
L.H.S of Equation (1)= 1 2 × 2.5 + 3 × (-3.4)
= 30 -10.20
= 19.80≠ R.H.S that is 40.
Similarly, L H S of equation (2)= 7 × (2.5) - 4 × (-3.4)
= 17.5 +13.6
= 31.1≠R HS that is 38
So, you can Write with 100 % confidence that point (2.5, -3.4) is not a solution of this system of the equation.
Answer:
x=1638831.492383738758729e+23f+0
Step-by-step explanation:
(1123)(x)=983298f+(220.22)(38)
Step 1: Divide both sides by 8.954302432552374e+23.
8.954302432552374e+23x
8.954302432552374e+23
=
983298f+1842545.52
8.954302432552374e+23
x=
163883
1.492383738758729e+23
f+0
Answer:
P [ β / Def] = 0,6521 or 65,21 %
Step-by-step explanation:
Tree diagram:
0,20 (α) Defective 0,02
0,50 (β) defective 0,06
0,30 (γ) defective 0,04
According to Baye´s Theorem
P [ A/B] = P[A] * P [ B/A] / P[B]
if we call
β = A and Defective = B then P[β] = P[A] and P[Defective] = P[B]
we get :
P [ β / Def] = P[β] * P [ def./β] / P[def]
Then
P[β] = 0,5
P[def/β] = 0,06
P [Defective] = 0,02* 0,2 + 0,06*0,5 + 0,04*0,3
P [Defective] = 0,004 + 0,03 + 0,012
P [Defective] = 0,046
P [ β / Def] = 0,5 * 0,06 / 0,046
P [ β / Def] = 0,6521 or 65,21 %
Answer:
5*4.95= 24.75
$24.75
Step-by-step explanation:
You are going to multiply 5 by 4.95